there's probably some very clever way of attacking this but by the time you figure out what that is you'll have solved it by brute force and be off savoring a margarita.
First let's see what multiples of 99 are 4 digits. There can't be all that many of them.
99 x 11 = 1089 is the first one, 99 x 101 = 9999 is the last one, so 90 all together.
In this day and age of fast software I'd just code up a quick little program to see which of these are palindromes.
I come up with
{1881, 2772, 3663, 4554, 5445, 6336, 7227, 8118, 9009, 9999}
Now how many 4 digit palindromes are there. Well you're basically choosing 2 numbers.
The first digit can be 1-9, and the 2nd can be 0-9, so we've got 9x10 = 90 total palindromes. Thus
p = 10/90 = 1/9
THAT'S funny! Some people ask upwards of 10 Q's per post......definitely discouraged if you want ANY answers! PLEASE....only one or two per post THANX ! 
