All Answers 352701 Answers

I believe it !  

Look at the graph here, Leaded : 

https://www.desmos.com/calculator/gapq6o4w2i

The dark area in the middle is the feasible region....

On your graph, it appears that the points in this area are :

(2, 4)

(-3, 5)

You have played 20 games

Each additional week you will play 4 games

Let W  be the number of additional weeks it takes to win at least 65% of your games

So......we want to solve this

Total Wins  / Total Games  ≥ .65

[ 3 + 3W]

_________ ≥  .65            multiply both sides by 20 + 4W

[ 20 + 4W ]

3 + 3W ≥  .65 [ 20 + 4W]

3 + 3W ≥ 13 + 2.6W    subtract 3, 2.6W from each side

.4W ≥  10       divide both sides by .4

W ≥ 25  ⇒  you must play at least 25 + 5  =    30 weeks to win 65% of your games for the first time

Correct!!!!....I forgot  about the interval notation.......!!!!

This graph may help you, Leaded : 

https://www.desmos.com/calculator/o5nyleiqox

Thanks!

3x-7  ≤   5x+9   subtract  5x from both sides

-2x  - 7  ≤  9      add 7 to both sides

-2x  ≤  16       

Divide both sides by -2  and reverse the inequality sign [ since we are dividing an inequality by a negative  ] 

x ≥  -8

35000 x 2000   =

3.5 x 10^4  x  2 x 10^3   =

3.5 x 2 x 10^4 x 10^3   =

7.0 x  10^7  lbs

We have this

H   =   -16t^2  - 30t + 900

Where H is the height after t seconds

The derivative of this is the velocity

H'  =  -32t - 30

After 5 seconds, the velocity is

-32(5) - 30   =

-190 ft/ s

To find the time to hit the ground....set H = 0

-16t^2 - 30t + 900   = 0

-8t^2  - 15t  + 450  =  0

8t^2 + 15t - 450  = 0

The positive solution to this is ≈ 6.62 sec

The velocity at this time is    -32(6.62) - 30 ≈   -241.8  ft/sec

I assume you want to write the equation of a line....

y  =   4  ( x - 1) + 9       simplify

y  =  4x  - 4   + 9

y =  4x   + 5

P(< 20)  = [ 120 - 90 ] / 120    =   30 / 120    =   1 / 4

a=1; b=listfor(n, 1, 3, (n^2/2010))

(0.0004975124378109452736318407960199004975124378109452736318407960199004975124378109452736318407960199005, 
0.001990049751243781094527363184079601990049751243781094527363184079601990049751243781094527363184079602, 
0.004477611940298507462686567164179104477611940298507462686567164179104477611940298507462686567164179104)

P.S. I ran them on my computer and ALL of them repeat!!. And their "period" of repeats is exactly the same for ALL of them - that is, they ALL repeat every 33 DIGITS. Look at the 3 examples above(1^2/2010, 2^2/2010, 3^2/2010), which I have calculated to 100 decimal places and observe that they ALL repeat every 33 digits. What is the "mathematical explanation" for it, that I honestly don't know? Maybe somebody like heureka, Alan and other Mods might have an explanation. It might have something to do with 2010 itself. Try factoring it and this is what you get: 2010 = 2 * 3 * 5 * 67. Notice that it has 4 distinct prime factors multiplied together. I believe that is the reason it repeats every 33 digits, because its largest factor is 67 and 33 is 67/2 nearly!!

Thank you so much!

Yup, that was the same answer on the website!

Distance  / Speed  =  Time

Can you solve it knowing this???

"D"   .....$250

sin θ  =   x / 10

arcsin ( x /10)   =   θ

maybe but thanks for trying at least! :)

$1,785.42, plus 6.635% tax  less  $800  =

1785.42 * 1.06635  -  800  =

$1103.88

Confusing to me too, NSS   !!!

Gross Amt Due From Borrower = 1 + 2   =  121,491.04

Total Paid By Borrower  =  4 + 5 + 6   = 95505.36

The difference in these is what the borrower owes  =  25985.68

It appears that the borrower paid  95505.36  upfront

I don't know if this is considered all cash, or not

Maybe someone else knows   ????

a)     P  = 8500 ( 1 - .045)^t

Where  P   is the population  "t" years after 2010

b)   7000 =   8500 ( 1 - .045)^t

Divide both sides by 8500

7000/8500 =  ( 1 - .045)^t

Take the log of both sides

log (700/8500)  =  log ( 1 -.045)^t

And by a log property we can write

log ( 7000/8500) = t * log (1 - .045)

Divide both sides by  log ( 1 - .045)

t  =   log ( 7000/8500) / log (1 - .045) ≈  4.2 years

So....the population will be 7000  in about  2014

Future Population=FP
Present Population=PP
FP = PP x [1 + (-0.045)]^t - Town's population t years after 2010
7,000 = 8,500 x [1 - 0.045]^t
7,000 = 8,500 x       0.955^t    Divide both sides by 8,500
0.8235294 = 0.955^t                Take the log of both sides
t =Log(0.8235294) / Log(0.955)
t =4.22 =~4 years after 2010.