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, sorry but the right answer is 3.4

P ( mult 4 or 5) =

P ( mult 4) +  P (mult 5)  - P (mult 4 and 5) =

10/40   + 8/40  - 2/40 =

16 / 40  =

2 / 5

P ( mult 3 or 4) = 

P(mult of 3)  + P(mult of 4)  - P(mult 3 and 4) =

13/40  +  10/40   -  3/40  =

20 / 40  =

1 / 2

**********

thx!

Is the median supposed to be 10 ???

If so.,...

Don't know if my answer was correct, but see here :

https://web2.0calc.com/questions/please-help_84347

Odd title, but okay...

Does 440/4 equal 300/3?

You are very welcome!

:P

Welcome aboard, shrek.....!!!!

1.  In Triangle ABC, the circumcenter and orthocenter are collinear with vertex A. Which of the following statements must be true?

I believe that "2"  is true

The circumcenter is located at the intersection of the perpendicular bisectors of the sides of a triangle

The orthocenter is located at the intersection of the altitudes of a triangle

But, in an equilateral triangle, the perpendicular bisectors of the sides and the altitudes are the same

The Radius  =  (1/2) Diameter =  (1/2)(18x) = 9x

Area  =   

pi  * (Radius)^2  =

pi * ( 9x)^2   =

pi * 81x^2 =

81 * pi * x^2

Total travel time  (in minutes )  =   

35   + 55   +  2hrs 55min  =

35  +  55  +  120  +  55  =

265 min  =    265 /60 =   240/ 60 + 25/60   =  4 hr 25 min

4 hrs 25 min  = total travel time

4 hrs before 10:35 AM =  6:35 AM

And   25 minutes before this is  

6:10 AM   =  time she started traveling

35 minutes + 55 minutes + 175 minutes = 265 minutes

It took 265 minutes or 4 hours and 25 minutes to get to her grandmother.

10-4 = 6

35 - 25 = 10

Jean left her house at 6:10 A.M.

Remove the first part. Collect like terms and multiply by LCM. 

For me, the good morning is a good afternoon

If Solo weighs \(x\) pounds, then Sparky weighs \(7x\) pounds.

- PM

Hey.....that's what WE'RE here for......to help you out...LOL!!!

thanks I suck at algebra

OK...we have....

V   =     L         *        W         *       H        =

         (2x^2)    *    (2x^3)    *         5x          =

                      4x^5           *           5x         =

                                 20 x^6

What’s the answer you got for this since you’ve taken the test. Help please

Imagine, for convenience sake, that there are 100 children at  the school

So  8 have both

We have this

Number Total =  Total Number Umbrellas +Total  Number Raincoats - Number Both

Let x be the number with raincoats.....so 2x = number with umbrellas

So we have

100  =   2x   + x     -   8     rearrange as

108  = 3x           divide both sides by 3

36 = x

And the number with umbrellas  = 2(36) = 72

But 8 of these have both....

So....the number with only umbrellas is   72 - 8  =  64  =   64/ 100  =  64%

Here's a Venn Diagram

xxxxxxxxxxxxx

BX = 2sqrt(13) =   sqrt (52) = CX

And since AX is a median,  OX = (1/3)12 =  4

And since triangle OBX is right

OB = sqrt (BX^2 - OX^2) =  sqrt (52 - 16) = sqrt (36) = 6

sin OXB = sin OXC =  OB/BX =  6 / [ 2sqrt (13)] =   3 /sqrt (13)

Note that  angle OXC is obtuse....so its cosine is negative

And cos OXC =   - sqrt [ 1 - sin^2 OXC ]  = -sqrt [ 1 - 9/13] = -sqrt (4 /13] =  -2/sqrt (13)

Using the Law of Cosines

OC^2  = OX^2  + CX^2 - 2( OX * CX) cos OXC

OC^2 =  4^2 + 52 - 2  [4 * 2sqrt(13) ] (-2/sqrt (13)   

OC^2  =   16 + 52 - 2 [ 4*2 ] (-2)  

OC^2 =  16 + 52 + 32 

OC^2 = 100

OC = 10

And this is 2/3 of  CZ ....so....

(2/3)CZ = 10

CZ =  15

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