a. Solve the equation (x+3)(x-3) = x-3
x^2 - 9 = x - 3
x^2 -x - 6 = 0
(x -3) ( x + 2) = 0
Settting each factor to 0 and solving for x gives that x = 3 and x = -2
b. These are the x coordinates of the intersections of both functions
c. g(x) = h(x)
-.5x^2 + x + 3 = x - 3
-.5x^2 + 6 = 0
.5x^2 = 6
x^2 = 12
x = ±√12 = ±2√3
