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Second one......We have to be a little creative, here, RP....this one is a little harder than the others!!!

Let the center of the circle be O

And when we draw radii OJ and OL to the tangents...  then angles  KLO and KJO  = 90° each

So....they sum to 180°

This means that in quadilateral KJOL....angles JKL and central angle JOL make up the remaining 180°

So  JKL and JOL = 360 - 90 - 90 = 180°

But  measure of central angle JOL  and major arc  JML = 360

So

angle JKL +  angle JOL = 180        (1)

Arc JML + angle JOL = 360   (2)

When we subtract (1) from (2)  we have that

Arc JML - angle JKL =  180      ....so...

(25x - 13) - ( 8x - 6) =  180        simplify

17x - 7 = 180

17x = 187

x = 11

So    arc JML  =  25(11) - 13  =  262°

BTW...here's a resource that may help with some of these : https://www.mathwarehouse.com/geometry/circle/tangents-secants-arcs-angles.php

First one....we have the Secant-Tangent Theorem that says that

measure angle RST =  (1/2)  [ measure of arc QT - measure of arc RT ]

So we have

(10x - 2) = (1/2)  [ ( 27x + 3) - ( 9x - 5) ]      multiply both sides by 2

2(10x - 2)  = (27x  + 3) - (9x - 5)        simplify

20x - 4  =     18x + 8

2x = 12

x = 6

So  arc RT = 9(6) - 5   = 54 - 5 =   49°

To find the y intercept....just let x = 0

y =  4(0) - 6

y = - 6

So..the y intercept = (0, - 6)

B

2

X

1

A     1    Y     2          C

Note that BAY  and XAC are right triangles...so....

We have tthis system

(3AX)^2 + (AY)^2 =  16^2         and

(AX)^2 +  (3AY)^2 = 28^2

Simplify

9AX^2 + (AY)^2 =   256   →   -81AX^2 - 9AY^2  = -2304      (1)

AX^2 +  9AY^2 =  784      (2)

Add (1)  and (2)

-80AX^2 = -1520

AX^2 =  -1520/ -80  = 19

AX = sqrt (19)

So...3AX = 3sqrt(19) = AB = sqrt (171)

And  

AX^2 + 9AY^2 = 784

19 + 9AY^2  784

9AY^2 = 765

AY^2 = 85

AY = sqrt (85)

So ....3AY = 3sqrt(85)  = AC = sqrt (765)

So....the hypotenuse BC =   sqrt ( AB^2 + AC^2)    =  sqrt (171 + 765 ) = sqrt (936) = 

sqrt (2^3 * 3^2 * 13)  = 2*3 sqrt (2 * 13) = 6sqrt (26)  units

D.a line that shows the set of all solutions to the equation.

720 seconds x  1 hr  / 60 min    x  1 min / 60 sec

720 / 3600 hrs  =  1/5 hr

Note....720 seconds isn't 12 hrs....it is  (1/5) hr  = 12 min

"B" is correct

f(x) =  [ 1 + 2x] / x

Note that when x = 1, y = 3

So..the point (1,3) is on f(x)

This indicates that the first graph must be correct

And 

g(x) = 2 + x 

Note that when x = 0, y = 2

So...the point   (0, 2) is on g(x)

So....the first graph must be correct because (0, 2) isn't on the second graph of g(x)

Can you take it from here ???

C 5350 feet

True does not require that much but at least she proves her math and gives a detailed expination of her math. Its detailed so it could help someone through the process if wanting to solve this problem. 

Well....it would be C  if it were

t =  -3h + 25

EW is correct...a literal equation usually involves several variables....we are not trying to find a numerical answer...rather....we are using the equation to (usually) solve for a variable

A.  not an equation

B. We can find a numerical  value for x....so...not literal

C. this is an identity

D is literal.....we can use it to  solve for either x or y

There's nothing to solve...

This is just the formula for the volume of a cylinder

Scond one....this is a little tricky !!!

Note that :

measure of angle WXZ +measure of angle  WXY = 180

(5x + 36) + WXY = 180

WXY = 180 - 5x - 36

WXY =  (144 - 5x)

And we can apply the Tangent Chord Theorem  that says that

2 * measure of angle WXY =  measure of  arc WX

And arc WX + arc WVX = 360

So we have 

2(144 - 5x) + (13x + 9)  = 360     simplify

288 - 10x + 13x + 9 = 360

297  + 3x = 360

3x = 63

x = 21

So....angle WXY =  ( 144 - 5(21) )   =  144 - 105  =  39°