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What do you mean by "rent"? Do you want the semi-annual payments made to get the balance of $9,000 after 9 years @ 4% compounded semi-annually?

ok :)

Thanks,

I wasn't twigging with the \overline z bit.  I just didn't think about the Latex conversion properly, it comes out on a new line for me so I overlooked it.  

If I may be allowed to regard the word "dreamy" as having connotations similar to those of "reminiscent" and "wistful" then B. would come closest to describing the tone of the paragraph.  Also, I think there are more adjectives than would properly be used in a formal writing.  

dreamy

8 c  3     *   6 c 2 =   56 * 15  =   840 ways

Compute the length of the minor axis of the ellipse.

Correct answer:

\({10\choose 5}=\dfrac{10\cdot9\cdot8\cdot7\cdot6}{5\cdot4\cdot3\cdot2\cdot1}=9\cdot 4\cdot 7=\boxed{252}\)

nvm, i got it

Melody, the first answer up there is mine.  I thought the OP was talking about the calculator on this site. 

!

We have to place an isosceles triangle, 45-45-90 triangle such that the center of the isosceles triangle is the center of the square. The only way to do this is by rotating the isosceles triangles, such that the side is opposite the 90-degree angle. This is 1/4 of the total square or 1/4*100-25 square units.

Welcome back, hectictar!

we're told that both points lie on the line

\(a z + b \bar{z} = 38\)

\(\text{So just plug both of these points into the formula there and we solve for }a \text{ and }b\\ \text{I use the complex conjugate because that's how they've specified the line}\)

x²-5x-64=2 ⇒ x²-5x-66=0 ⇒ (x-11)(x+6)=0. x = -6 is the only negative solution.

x²-6x+10=2 ⇒ x²-6x+8=0 ⇒ (x-4)(x-2)=0.  x = 4 and x = 2 are both positive solutions.

Hence three solutions in total.

How do u subsitute?

No, thats not right

It should be on all scientific calculators.  Which one are you using?

I am a middle schooler who likes math a lot, so I just learn as much as I can.

On an online calculator, that would work.

I need help finding the factorial function on the calculator. I appreciate your feedback. Thanks!

I couldn't find a button on the calculator, but it works if you just type in the factorial symbol, i.e., the exclamation mark. 

Example:  In the "answer field" (I don't know what else to call it.) of the calculator, type in a 4 and then on your computer keyboard hold down the Shift key and tap the "1" key to insert an exclamation mark.  The field will then look like this:  4!   Next, just click the equals button.  The "answer field" will then display 24 which is 4 factorial.

Try it with a few small numbers to gain confidence that it actually works and is accurate. 

Summary:  For calculating a factorial, type in the exclamation mark from your keyboard. 

!

The answers are not going to be exact but

For midline I would add the 6 numbers and then divide by 6 to get the average.

The amplitude is decreasing over time so I don't think you can give it a set value.

The period is the time taken for the wave to start repeating itself.

the crests seem to be at about  

4am on the 26th April,    4am on the 27th april,  4am on the 28th April. ....   etc

So what do you think the period is?

Yes it is excellent to see you back again Hectictar!

What is your question?

Which term do you want?

The widest measurement of a square is the diagonal

The diagonal is 8

So you have a right angled, isosceles triangle with hypotenuse=8    (the legs are 2 sides of the square)

Now you sketch it and then try  to work it out for yourself.

Please no one answer over me.

1) How many zeroes does 66! end in when written in base 12?

I think that this is an easier way to express the question.

66!=k*12^n       k is a positive integer and so is n.   Find the largest value of n

12=2*2*3

We have the factors 1 to 66

half of those are divisable by 2  that is 33 of them

So now I will divide those ones  by 2 and I get the numbers 1 to 33

ok , 16 of those are divisable by 2

So I will divide those by 2 again and I get the numbers 1 to 16

8 of these will be divisable by 2

Divide these by 2 again and I get the numbers 1 to 8

4 of these will be divisable by 2

Divide these by 2 again and I get the numbers 1 to 4

2 of these will be divisable by 2

Divide these by 2 again and I get the numbers 1 to 2

1 of these will be divisable by 2

33+16+8+4+2+1 = 64       

So the highest power of 2 that goes into 66! is    2^64     

so

mod(66!,2^64) = 0

mod(66!,4^32) = 0

Now I need to look for the highest power of 3 that will go into 66!

We have the factors 1 to 66

One third of those are divisable by 3  that is 22 of them

So now I will divide those ones  by 3 and I get the numbers 1 to 22

ok , 7 of those are divisable by 3

So now I will divide those ones  by 3 and I get the numbers 1 to 7

ok , 2 of those are divisable by 3

So I will divide those by 3 again and I get the numbers 1 to 2

0 of these will be divisable by 2

22+7+2= 31         

So the highest power of 3 that goes into 66! is      3^31 

mod(66!,3^31) = 0

mod(66!,12^31) = 0

So it looks to me like there will be 31 zeros.