All Answers 358181 Answers

He responded to your teaching post by biting you on theass.   

I’ll answer anyway ...

Tommarvoloriddle doen’t present as an intellectual pig –not so far, anyway.

As for being a moron, he’s the right age for it, so he gets a free pass.  Leaving behind moronic thought processes, and learning how to think logically and analytically is a gradual process.  

Teaching these critical thinking skills is time consuming, but the investment of time is well worth it, because the juvenile brain will literally grow and develop around these skills. For children with average intelligence, these skills will put them at the head of their class. For children with augmented intelligence, this will eventually put them in the 90^th percentile of testable academic intelligence. 

 Tomm has a bloody long way to go, but these skills will speed up his trip. 

GA

Just asking –my ass! I know it’s you JB. 

GingerAle, 

you’ve commented before that teaching pigs to sing is a waste of time and it annoys the pigs.

Why are you wasting your time with morons?   Just asking.

BECAUSE I wanted you to figure it out yourself! I don’t mind pealing and cutting bananas for you, but you are a big boy now, so you need to learn how to chew them all by yourself.

Yes, I could have posted a single sentence –in five languages, including Latin. Would you have understood it? Would you then have an instant understanding of how to translate words into mathematics?

GA

THX, EP.....your answer is the correct one  !!!

Number of 3 digit integers =   999-100 +1 = 900

900/6 = 150 of them are divisible by 6

9 x 10 = 90 of them end in 6

every third one is divisible by 6    so 30         30/90 = 1/3   of the three digit numbers that end in 6 (given) are divisible by 6

Travisio, do not use this forum to get all your homework done for you - no matter what subject!

Do not ask any more of these questions in the remotely near future. 

thx!!!

why didn't you just say so? You could have used a senctence to get that statement out more clearly.  Just saying.

I think that they know that Christian people have souls...

Maybe they view them as weird mules who won't follow their belive system?

nioce, travisio...

Ax =  2x

A * Ax   =  A * (2x)  = 2(Ax) = 2(2x)  = 4x = A²x

A * A²x  =  A* (4x)  =  4(Ax)  = 4(2x) = 8x  = A³x

A * A³x  =  A(8x)  = 8 (Ax)  = 8(2x) = 16x = A⁴x

A * A⁴x  =  A(16x)  = 16 (Ax)  = 16 (2x)  = 32x  = A⁵x

A * A⁵x  =  A (32x)  = 32(Ax)  = 32(2x) = 64x  = A⁶x

A * A⁶x  =  A(64x) = 64(Ax)  = 64 (2x) = 128x = A⁷x

So.....m  = 128

Correction.....thx, heureka!!!

okay i did and also khan acadamy also

B. 

For more info(if your a nerd like me)go to: https://www.britannica.com/topic/Sufism

It's really interesting- I learned a bunch from this.

-\(tommarvoloriddle\)

Thank you GingerAle.

OPTIONS:

-do it later

-refresh

-quit tab and make it again

I had the same problem... My original tried username was bananamaster029...

-\(tommarvoloriddle \)

Try to register later....I kept getting this error with the calculator, too....

It now seems to be cleared up.....

9^2004   =   (10 - 1)^2004

So....the binomial expansion is

10^2004 - C(2004, 1) * 10^2003  + C(2004, 2)*10^2002 -  ..... - C(2004,2002)(10)^2  + C(2004, 2003) (10) -  1 

All of the terms except the last three end in  "000"...so they add nothing to the sum of the last two digits in the expansion

And the last three terms are

-200,700,600 + 20040 - 1  =

 abs   [ -600 + 40 -  1  ]

abs [ -601 + 40  ]    =

abs  [-561 ]  =

561

And the sum of the tens and the units digits in the expansion  =  7

To be divisible by 6, the fist two integers must be divisible by 3......so...we can solve this for n

126 + 30 * (n)  = 999

30 *  (n)  = 873     divide both sides by 30

 (n)  = 29.1

Take the ceiling of 29.1  =  30

So....30  three-digit integers ending in "6"  are divisible by 6

And we have  999 -100 + 1  =  900 three-digit integers

So....the probability is  30  / 900  =   1 / 30

See EP's answer below....!!!!

OK, young person, here is my best "guess"!

Since n is 2^100, or power of 2, all ODD numbers under 2^100 are "relatively prime" to it, which means: 2^100 / 2 =2^99   numbers that are relatively prime to 2^100.

https://en.wikipedia.org/wiki/Euler%27s_totient_function

You are correct....I originally had 01 in there, but it got deleted while I was formatting my answer before posting.....fixed it...THANX !   ~EP

Yes they were not part of the questions

Travis Richardson