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#1
0
Never mind. Figured it out.
Guest
Jan 9, 2013
Jan 8, 2013
#1
+3146
0
[input]plot( abs( -2x-1 ), 7, x=-4..4 )[/input]
solve: -2x-1 = 7 and -(-2x-1) = 7
-2x-1 = 7
-2x-1+1 = 7+1
-2x = 8
-2x/-2 = 8/-2
x = -4
-(-2x-1) = 7
2x+1 = 7
2x+1-1 = 7-1
2x = 6
x = 6/2
x = 3
admin
Jan 8, 2013
#1
0
cuberoot (-162) = - cuberoot (27 * 6) = - cuberoot (3^3 * 6) = -3 * cuberoot(6)
cuberoot (16xy) = cuberoot (8*2xy) = cuberoot (2^3 *2xy) = 2 * cuberoot (2xy)
Guest
Jan 8, 2013
#2
0
its 20, 4x4 is 16, + another 4x4 is 32, +4 is 36, then takeaway 4x4 (which we already know equals 16) is 20
Guest
Jan 8, 2013
Jan 7, 2013
#1
0
asdf
Guest
Jan 7, 2013
#1
0
choose equation solver and write -350000+160000*e^(0.015*x)) and solve...
Guest
Jan 7, 2013
#1
0
.
Guest
Jan 7, 2013
Jan 6, 2013
#1
0
not not not not not not
Guest
Jan 6, 2013
#1
0
( a + b )2 = a2 + 2ab + b2
( a - b )2 = a2 - 2ab + b2
( a + b ) ( a - b ) = a2 - b2
Guest
Jan 6, 2013
Jan 5, 2013
#1
0
| 3 7 0 | |x| | 12 |
| 2 -5 0 | |y| = | -7 |
| 5 0 2 | |z| | 3 |
Guest
Jan 5, 2013
#3
0
sorry the actual question is [sqrt(1-cot^2x)*sqrt(sec^2x-1)]/cos x= tan^2x
Guest
Jan 5, 2013
#2
0
show that [sqrt(1-cot^2x)*sqrt(sec^2x-1)]/cos x= tan 2x
Guest
Jan 5, 2013
#1
0
you solve by:
first add 4y to both sides
then subtract 12 from both sides
next you divide all by 4
answer should be y=3/4x + 3
hope this helps
Guest
Jan 5, 2013
#2
+3146
0
[input]3.108*((6.62*10^-34)/(1.938*10^-18))[/input]
[input]3.108*((6.62e-34)/(1.938e-18))[/input]
[input]0.00000000000000106165944272445820433[/input]
admin
Jan 5, 2013
#1
0
Je ne parle pas français, mais si vous lisez l'anglais il ya un lien vers «Aide» sur la page calculatrice qui peut vous guider. Bonne chance.
Guest
Jan 5, 2013
#1
0
if the problem is
[sqrt(1 - {cot(x) * cot(x)}) * sqrt(1 - {tan(x) * tan(x)})] / cos(x) = tan(2x)
and the angles are real numbers,
then it is NOT an identity. in fact, it is NEVER true, which would make it an ANTI-IDENTITY, i suppose.
nice try though
(for those interested - plug in a few angles to see what happens)
Guest
Jan 5, 2013
#1
0
yes, there is a difference.
because |4 - 7| = 3 and (4 - 7) = -3, the solutions (of the two problems) will differ.
|4 - 7| - |8 - 2| = 3 - 6 = -3, while (4 - 7) - (8 - 2) = -3 - 6 = -9.
(notice that |8 - 2| = (8 - 2), since 8 - 2 is positive.)
Guest
Jan 5, 2013
#4
0
Hello:
3y-4-5y=2y+4 please help!!!
-2y-4=2y+4
-4y=8
y=-2
Guest
Jan 5, 2013
#10
0
when you enter
6/(2(2+1)) in any calculator than the answer will be 1.
and
6/2(2+1) in any calculator than the answer will be 9.
It is not the stupid question by any way at all.
Guest
Jan 5, 2013
Jan 4, 2013
#3
0
sorry, y= -2
Guest
Jan 4, 2013
#2
0
y=2
Guest
Jan 4, 2013
#1
0
hi
Guest
Jan 4, 2013
#1
0
10 1/3
Guest
Jan 4, 2013
#1
0
6y=8
Guest
Jan 4, 2013
Jan 3, 2013
#2
+3146
0
25*2-54:X=56
":" is the wrong operation in this context, use "/" instead:
[input]25*2-54/X=56[/input]
admin
Jan 3, 2013
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