The number of ways is C(10,4)*C(9,4) = 26460.
Thank you, CPhill !
( n + 1)^2
_________
n + 23
Note that, using the denominator , we can write n^2 + 2n + 1 as ( n + 23) ( n - 21) + 484
So we can write
( n + 23) ( n - 21) + 484
____________________ =
(n + 23) ( n - 21) 484
______________ + ______ =
n + 23 n + 23
( n - 21) + 484
_______
The factors of 484 are 1, 2 , 11, 22, 44, 121, 242 , 484
So we will have an postive integer when
n + 23 = 44 ⇒ n = 21
n + 23 = 121 ⇒ n = 98
n + 23 = 242 ⇒ n = 219
n + 23 = 484 ⇒ n = 461
And the sum is 21 + 98 + 219 + 461 = 799
Some children can get no candies
The twins must get only one piece each else there will not be enough for every child
that leaves 4 pieces for 3 children
one child will receive 2 pieces .....there are 3 ways to do this and the others will receive 1 piece
Three ways.
fun fact
the standard equation for a line is y=mx+b and the slope is always m so use that next time :))
WOAH thats smart too thanks CPhill!!
Thanks Guest.
I am still a big confused.
You have made some little error statements like it is f(0)=a without the absolute signs.
BUT
I think my main problem is that i do not understand root theory well. So I probably need to do some study.
The slope of "p" is 0.12
Since n's slope is 0.1 greater, then its slope is 0.12 + 0.10 = .22
Eight times the square of my age, plus eight times the same, is equal to sixteen. Which is the total age?
I'm sure that there is a general way to solve this....but ...let the polynomial be
-3x^2 + 9x - 5
So
P(2 + i) =
-3 ( 2 + i)^2 + 9 (2 + i) - 5 =
-3 (4 + 4i + i^2) + 9(2 + i) - 5 =
-3 ( 3 + 4i) + 18 + 9i - 5 =
-9 - 12i + 18 + 9i - 5 =
4 - 3i
P ( 2 -i) =
-3 (2 - i)^2 + 9(2 - i) - 5 =
-3 (4 - 4i + i^2) + 18 - 9i - 5 =
-3 ( 3 - 4i) + 18 - 9i - 5 =
-9 + 12i + 18 - 9i - 5 =
4 + 3i
Cross with two puffins
come back with ONE puffin
cross with one penguin
take the puffin back
cross with two puffins
take one puffin back
cross with second penguin
get a new boat
Here's a way to figure this
2^1 = 2
2^2 = 4
2 * 3 = 6
2^2 * 3 = 12
2* 7 = 14
2^2 * 7 = 28
2 * 3 * 7 = 42
2^2 *3 * 7 = 84
2*7^2 = 98
2^2 * 7^2 = 196
2 *3 * 7^2 = 294
2^2 * 3 * 7^2 = 588
[ Note....negative factors are not "natural" numbers ]
oh thats smart.. thank you!!
OOPS...I made a mistake.....let me fix that !!!
THX for the correction!!!
We have
C(100, 98) * (x)^98 * (2)^(100 - 98) =
C(100, 98) * x^98 * 2^2 =
4950 * x^98 * 4 =
19800 x^98
4 x 3 x 49 = 588
Factors (from a website):
1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 49, 84, 98, 147, 196, 294, 588, -1, -2, -3, -4, -6, -7, -12, -14, -21, -28, -42, -49, -84, -98, -147, -196, -294, -588 Pick the ones you like and count them up !
Is THAT a math question , Chris? 1 out of 10 probability, maybe?
Not many I would wager ! Haha
LOL!!!!!!
[ I wonder how many of the younger members get the reference ??? ]
Ignore the statement "the club is choosing a committee of 44 members"
We already have "24 male and 20 female members"
Since we have 24 male members in the club, we only need to worry about female members.
So how many ways can we choose 20 out of 24?
24!/(4!)(20!) = 10626
Chris, I'm baffled. How is the width 4 radii? It looks like 3 to me. ~scratching my head~
.
Speak, Lassie , speak ! What ? Timmie has fallen down a well ???
Not sure here is my guess 99 x 99 = 9801 ?
SOmeone KNOW the answer?
How many ways can you choose 20 females out of a pool of 24 ? 24 c 20 = 10626
24 males out of a pool of 24 ? 24 c 24 = 1 (duh !)
10626 ways
