Response to first answer.
y = 4-3 sin (x/4)
"The first highest point should be seven. The first lowest point should be one, correct?"
Correct except I wanted the actual points, so i want the x value as well as the y value at the highest point.
Sketch it freehand and see what you get, then check with desmos.
second response:
y = f cos (gx) -t
We are both in full agreement that the amplitude is f. So that is good.
im going to substitute some constants to help with the other features.
let f=4, g=2 and t = 3
then you would have
y=4cos (2x) - 3
Sketch freehand, you should be able to. Then check with desmos.
y=4cos(2x)-3 | y = f cos (gx) -t | |
amplitude | 4 | f |
midline | ||
y intercept (remember this is a cos graph) | ||
is the y intercept at the top middle or bottom? | ||
wavelength \(\lambda\) | ||
A maximum point | ||
A minimum point |
By the way, I do understand that these new concepts are very hard for you. And I am happy to keep helping you to understand.
You need to understand that when you get each concept you need to practice, practice, practice, or else it will not sink in.
You can practice by making up your own similar questions, doing them yourself, and then checking your answers with Desmos.
First Question:
The first highest point should be seven. The first lowest point should be one, correct?
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Second Question:
y = f cos (gx) -t | |
Amplitude | f |
y-intercept | t |
Midline | y = t |
Wavelength | (gx)*pi |
With what I'm understanding, we're using these as just placeholders, right? Thus, I can't give any specifics, or am I all wrong?
You have the right idea, but you have made a couple of mistakes.
put some numbers in yourself and see if you can spot your errors. :)
Amplitude is the only one that is completely correct.