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Oh, that was wrong. Somehow, it was 44,000 dollars

wow thx

it says its wrong

An edge of a square can be expressed as $4x-15$ meters or as $20-3x$ meters. What is its area in square meters?

Hello Paresh!

\((4x-15)^2=(20-3x)^2\\ 4x-15=20-3x\\ 7x=35 \)

\(x=5 \)

A=(4*5-15)*(20-3*5)=5*5

A=25m²

The area of the square it 25m²

  !

plz help

Let I be the value of  his internet stocks at the start of the year

Let P  be the value of his portfolio at the start of the  year

So......at the start of  the year  the value of his portfolio  was

I  +  10000  =  P       (1)

At the end of the year, since his portfolio  decreased  by 6%  from the start  of the year....it is now worth  .94P

And his internet stock is now worth 1.10 I   since it increased  by 10%

So.....at the end of the year we  have  that

1.10 I   + 9000   =.94P      (2)        sub (1)  into (2)

1.10 I   +  9000   =  .94  ( I + 10000)     simplify

1.10 I   + 9000  = .94 I  +  9400     subtract   9000,  .94 I    from both sides

.16 I  =   400        divide both sides  by   16

I   = $2500    =   value of internet stock at the start of the year

So....at  the end of the year, they were worth  1.10 * 2500  = $2750

Find height of right angle

sin 30 = 1/2  = height/(2 sqrt3)       height = sqrt3       

     Both legs of the triangle on the right are the same length (it is a  45 - 90 - 45 triangle)

use pythagorean principle to calculate x (which is the hypotenuse)

hyp^2 = x^2      =   (sqrt 3)²   + (sqrt3)²       You can take it from here !  

If the numerator is meant to be 2*(n!), the ratio of the n+1th term to the nth term becomes (n+1)/4. This is greater than 1 for all n>3, so the sum still diverges.  However, I think this interpretation of 2n! is unlikely.

One magnitude corresponds to a brightness factor of 2.512 times    The more NEGATIVE the BRIGHTER the object is....in this example A is much brighter than B....How much brighter?

3.03 -  - 19 = 22.03

22.03   x   2.512 =    A  is  ~55 times brighter  than B

pH = - log [H+]

3.63  = - log [H+]

10^-3.63 = H +  = .000234 gm/l

CPHill, you got it wrong. Try using casework.

Here is Venn:      You can see  A intersection B  is  '8'    one number out of  12 possibles     1/12

C(t) = 17  e^-kt       I will assume t  is hours

1/2 of the drug will be gone 28 hours   = 8.5 mg

8.5 mg  = 17 e^-k(28)      yields  k = .0247553

8AM to 4 PM is  8 hours   = t

17 e^-.0247553(8)  =  13.95 mg  still in pt at 4 pm

Did you try: [6sqrt(2) ]^2 / 2 =36 units^2

Can't see it.....requires sign in

which one

hyp^2  = a^2 + b^2

sqrt (hyp)  = 2

hyp = 4

hyp^2 = 16         then from above   a^2 + b^2 = 16