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non, il n'y a pas de bouton aleatoire

Instead  of  AD = sqrt(3)   should be  CD = sqrt(3)  

There are a total of \(6!\) ways to order the \(6\) lectures with no restriction. By symmetry, exactly half of these will have Dr. Jones's lecture before Dr. Smith's lecture. Thus there are \(\dfrac{6!}{2}=360\) ways to schedule the conference.

Good job, Guest!!!

Can Someone post the solution to #2?

Can you write the function. Can't read the numerator.

"Every time you replace a quarter with a nickel, you gain 0.20"

Darn it, I said it crossways.  I should have said every time you replace a nickel with a quarter. 

_π

says the answer is wrong

1000¹     has 3 zeroes  

1000²     has 6 zeroes

1000³     has 9 zeroes

1000¹⁰⁰    would have 300 zeroes

It is followed by 300 zeros. 

Let c be the number of cheese pizzas and p be the number of pepperoni pizzas.

By systems of equations, we have:

6c+7p=153.50

2c+2p=47.00

...........................................

c+p=23.50,   6c+6p=141.00

Thus, the cost of one pepperoni pizza is $12.50.

To get two of the same color, you need either two red or two green.

To get two red:      (3/10) x (4/9)  =  r

To get two green:  (7/10) x (5/9)  =  g

To get either two red or two green, add these results togethr:  r + g

I can't think straight..

the answer should be 7*7*7*7*4=9604 numbers.

If it took 8 persons, each working 36 minutes, to paint a wall,

then it took a grand total of  8 x 36  =  288 minutes.

If it takes a total of 288 minutes, and you have 18 persons,

divided equally, each person would work  288 / 18  =  16 minutes.

thank you

I have 54 coins in my pocket; some of them are quarters and the rest are nickels. In total, the coins are worth $6.10. How many of each coin do I have? 

You have 54 coins.  If they were all nickels, you'd have 2.70 

2.70 is 3.40 short of 6.10 so you need to replace some of the nickels with quarters. 

Every time you replace a quarter with a nickel, you gain 0.20 

How many 0.20 gains do you need to increase your total by 3.40? 

3.40/0.20 = 17 so it takes 17 of those gains to make 3.40 so you have  17 quarters 

The remaining number of coins is 54 – 17 = 37 so you have                   37 nickels 

_• 

3) Area of rectangle: 87.3*51.8=4522.14

    Perimeter of rectangle:87.3*2+51.6*2=277.8

a)The upper bound of the area, 4522.14, would be 4522.15, since anything less than that will round to 4522.1.

The answer would be 4522.15.

b)The lower bound of the perimeter, 277.8, would be 277.849 since that is the smallest number than will round down to 277.8.

The answer is 277.849.

2)

a) The lower bound of 16.4 would be 16.349, since that is the smallest number that will round down to 16.3

The answer would be 16.349

b)The lower bound of 21.58 would be 21.549, since that is the smallest number that will round down to 21.5

The answer would be 21.549.

This is a similar question that will definitely help you solve this problem.

Suggestion for the second question:

1)  Keep all the restraints (equations) for the original problem.

2)  Add these restraints:  s >= 250     e <= 200     e <= 300

3)  Graph all the original and the new equations and find their corner points.

4)  Place the values of these corner points into the revenue formula:  revenue  =  6e + 12s

     to find the maximum revenue.

Answer for the first question.

All maxima and minima have values at cornerpoints.

The cornerpoints are (125, 225), (125, 350), and (250, 100) for values of (e, s).

At e at $6.00 and s at $12.00 per liter, the revenue produced is:

point A:  (125, 225)  =  $3450.00      with s providing $2700.00

point B:  (125, 350)  =  $4950.00      with s providing $4200.00     <---  currently the max

point C:  (250, 100)  =  $2700.00      with s providing $1200.00

Increasing the price of e and keeping he price of s constant will never provide an amount for point A that is

larger than the amount for point B.

So, we just need to compare the amount of point B with the amount of point C.

Let E be the cost per liter of e.

point B:  amount:  125E + 4200

point C: amount:   250E + 1200

When will these two amount be the same?   125E + 4200  =  250E + 1200

                                                                                   3000  =  125E

 --->   E = $24.00 per liter

Below $24.00 per liter, point B is the max; above $24.00 per liter, point C is the max.