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(8.32-8)  /  8       x 100% = sales tax percentage 

5.6 rev   x    2pi rad/rev   /  (8 sec)        * 60 sec / 1 min    =    5.6 * 2pi * 60  / ( 80)  R / min  = .........

The points  (4,3)   and  (0,8)   are on the graph

Slope =   [ 8 - 3  ] /  [ 0 - 4  ]  =   5 / -4  =   -5 / 4

Using either point we have that

y = (-5/4)x  + 8

We  can write

log _y^5 (x^3)  = log _y (x^k)

Using  the change of base  theorem  we can  write

log x^3                log x^k          

_______   =     ________     simplify

log y^5                 log y

3 log  x            k log x

______  =    ________

5 log y              log y

(3/5) log (x) / log (y)   =  (k) log (x) / log (y)

So

(3/5)   = k

Given that x + y = 3 and x - y = 4, find 2x^2 + 2y^2.

First  one

Let  the width  of  the  box  = 25.5 cm

Let  the width of the disc = 1.6 cm

So

25.5 / 1.6  =    15.9375    means  that we could  not stack  16  discs  in the box....we  could only fit  15

Vi = E.e^-t/cr     (I believe you left out the negative in the exponent !)

                            You are given  E  = 10 v      c = 250 x 10^-6  FARADS        r = 3.3 ohms (?  dimensions left off in your Q)

                             Plugging into the given equation

V₀ = 10 e^{-0/(250 x10-6 * 3.3)}       this is the value of  V  at t= 0

V₁ = 10 e^{-1 /(250 x 10-6 * 3.3)}      this is the value of V  at t= 1 

etc    etc  for other  't' values

Start with the graph and show us what you find.....we'l go from there ! 

Translation by 5 units to the right.

HAHAHA!!!!.....most of the thanks  should go to Heureka!!!!

thank you 

Good!!!.....understanding is the  most important part...!!!

Ah....I didn't  notice  the "to  the  nearest cm"  thing

Let  the inner dimensions  be    14.5  x  27.5

And let the outside  dimensions   be as shown

The  max  for the blue  area is   (21) (42)  -  ( 14.5)(27.5)  =   882  - 398.75  =   483.25 cm^2

I understand now, thank you!

Yes, you did! I got the answer right!

You are given the RADIUS.    The can must be 3 DIAMETERS tall.......Can you 'figure it'  now?

LOL!!!....I just hope  that I found all of them!!!!!

Thank you so much! Now, I just need to make them as cases and solve it. Thank you CPhill! 

Here's what I get

2*3*4*5 +  1  = 121

2*3*4*(5 + 1)  =  24 * 6  = 144

2*3 * (4*5+ 1)  =  6 * 21  =  126

2*(3*4*5 + 1)   = 2 * 61  =   122

Latex please? Sorry, but I cannot read this.

My calculator said 0.02196969696

the first one it says its wrong

This worksheet will help you:

First  one

Blue  area =  area of large rectangle  - area of  smaller rectangle  = (21)(42)  - (15)(28)   = 

882  -  420   =

462  cm^2

Second  one

Assume  that  the log  =16m  =  1600  cm

Assume  that each fence post =  65 cm

So......the largest number of fence posts  that  can be  cut  from the log =  1600/65  =  24

Thanks Heureka and CPhill!

a)  Since he needs  to  varnish  both  sides the total area to be  varnished  is

      2* 12  * 8  *  3    =     24 * 24  =    576 ft^2

b)   Cost  =    area to be varnished  /  125   *  3.50      =    (576/125)  * 3.50  ≈  $16.13