The two pyramids are similar to one another.
the lengths of the sides are in the ration 1:2
so the surface areas are in the ratio 1:4 (I squared them)
The surface area of the whole thing is 1200 if I subtract the area of the base it is
1200-400=800
so the surface area of the top bit is 200
and the surface area of the base of the top bit is 100
So i think the surface area of the frustum is (800-200)+400+100 = 1100
I have not put any huge amount of thought into this. So maybe it is not right.
I assume you can plug the answer in and tell me if it is correct?