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A _____________________B

D _________________C

By alternate interior angles, DCA = CAB. All angles in a triangle add up to 180. Can you solve it?

How? Must be dark magic, or maybe a typo.

Hint:

Shaded = Square - 4 quarter circle

4 quarter circles = full circle

Full circle area = \({\pi}r^2\)

Square area = \(s^2\)

In this case, the side of the square is twice the radius of the circle.

As seen by the example f(x) = (x + 1)/(-x + 1), a + d = 2.

The complex numbers that work are 1, 1 + i, -1, and i.

mathway says it is equal to 2 + 3^(1/3).

Hint: It is a 45 - 45 - 90 triangle.

That means the area is (leg times leg) divided by two. The leg is \(\frac{6\sqrt{2}}{\sqrt{2}}\).

The answer is 100-25pi

T=Toby's age

THomas=3T

Terrence=T-13

T+3T+T-13=72

5T-13=72

5T=85

T=17

Toby is 17 years old.

I used mathway, but it said that it was out of it's reach. It cannot solve it.

Let the side lengths be x and y units.

x+y+x+y36

2x+2y=36

x+y=18

y=5x

6x=18

x=3

15*4=60..

32 pi + 8 pi = 40 pi.

Square A area: x*x=x^2

Square B area: 4x*4x=16x^2

x/16x^2=1/16- is the ratio between square A and square B.

First circle: pi(20)^2=400pi inches squared:

Second cirle"pi(20/2)^2=100 pi inches squared.

Thus, 400pi-100pi=300 pi inches squared(square inches).

PQ is a straight line, so It has to measure one-eighty(180) degrees.

x+x+x+x+x=180

5x=180

x=36

x=thrity-six(36) degrees.

90-y=10

y=90-10

y=80 degrees,

The measure of angle M is eighty(80) degrees,