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That was correct, thanks CPhill!

Yeah, that was correct...thanks! 

My answer is the same as what you said, I'm confused...

And I quote "that means that H is 1, E is 2, and S is 4."

Both CPhill and I have the same answer... I don't understand??

Wait...I understand, I found the values of E, H, and S but it wanted the sum in base 5 from the diagram. That makes sense.

Uh, I don't know why, but it said your answer was wrong. Here's the explanation they gave me:

Starting with the the rightmost column would be the easiest (we'll call it the first, the second rightmost column the second, and so on). Let's consider the possible values for E first.

Since the values must be non-zero, we'll start with 1. If E is 1, then S would be 1 and nothing would carry over. However, since H+H must equal E if nothing carries over and H must be an integer, E can not equal 1.

If E equals 2, then S must equal 4. H would then equal 1. This satisfies our original equation as shown.

I don't know what you did wrong, but hope that helps! Have a nice day :D

Here's my answer

https://web2.0calc.com/questions/number-theory-help_6

16t^2+55t+4= 30 feet is the equation we need to solve this problem. In this case, we'll be solving for t. 

16t^2+55t-26=0 since it does not factor, we'll have to do this out. 

Since our answer cannot be negative, our solution is 0.42113353947124876.

Rounding to the nearest 10th we get .4 as our final answer.

Hope it helps!

Let  S = 4   H  =  1   and  E  =   2

And we have  that

4  1  2₅

    1  2₅

______

 4  2  4₅

there are 8*10^6 = 8,000,000 total phone numbers

The question is actually easy if you think about it. S, H, and E have to be less than 5 since it's in base 5. If 2E=S, S equals either 2 or 4 and since 2H=E, that means that H is 1, E is 2, and S is 4. This is the only case that works. So your answer is 1+2+4= 7.

Hope it helps!

The equation of the parabola with vertex (h,k)(h,k) is y=a(−h+x)^2+ky=a(−h+x)^2+k.

Thus, the equation of the parabola is y=a(x+3)^2+1y=a(x+3)^2+1.

To find a, use the fact that the parabola passes through the point (−2,4)(−2,4): 4=a+14=a+1.

Solving this equation, we get that a=3a=3.

Thus, the equation of the parabola is y=3(x+3)2+1y=3(x+3)^2+1.

The  vertex form is

y  = a(x - h) ^2  +  k           where (h, k)  is  the  vertex  and (x,y) is a point on the graph

So

4 = a ( -2-  -3)^2 + 1              subtract 1 from both sides

3 = a ( 1)^2

3  = a (1)

a  = 3

So...the equation is

y = 3 ( x + 3)^2  + 1

3 was correct, thanks! :D 

3.4 repeating at the four... to base ten....

3+4/13+4/169+...

3+4/12

3+1/3

10/3..

I actually figured it out. It was 10/3. Sorry everyone! :( Please have a good day!

I think you're 1 off, 441 is NOT divisible by 11, you would get 1 mod(11) if you add 4.

If we visualive the diagram as a quadrilateral  with the sum of its angles at 360 degress we can solve this problem. Because the line that you reflect things on would have to be perpendicular to the point, we know that two angles would be 90 degress. We also know a third angle is 34 degress so all we need to do is subtract 2*90+34 from 360 to get 146 degrees as your answer.

Hope it helps!

2dd56 _ 6 to base ten is...

(2*6^3)+(d*6^2)+(d*6^1)+(5*6^0)=432+36d+6d+5=437+42d...

437 + 42d has to be divisible by eleven...

437 mod 11 = 8

Thus, the least number is d=3..

Yes, @below, I forgot. Thank you!

Thank you!

The base 6 number when converted to base 10 is 437+42d. From here, we try the numbers 1-5 to see what makes it a multiple of 11 and we get 3 as your answer.

Hope it helps!

x^4 - x^3 - 12x^2 - 3x + 1  = 0

1.  potential solutions  =   -1  or 1

2. The rational roots theorem  won't help here

We actually  have no  rational roots   

See  the (exact value) roots here calculated by WolframAlpha :

https://www.wolframalpha.com/input/?i=x%5E4+-+x%5E3+-+12x%5E2+-+3x+%2B+1%C2%A0+%3D+0

These are extremely messy......LOL!!!

Four(4) Identical balls and Four(4) identical boxes mean that the balls are indistinguishable and the boxes are also indistinguishable...

Since there is no restriction, let's try number separation.

1+1+1+1

1+1+2+0

2+2+0+0

1+3+0+0

4+0+0+0

Five(5) ways are possilbe.

Yup, it was correct. Thanks for re-working it out and also the explanation. :D Really appreciate it, and have a good day!

Since the balls are the same and the boxes are the same, the problem is basically how many ways can you get a sum of 4.

1+1+1+1

1+1+2

2+2

3+1

4

I get 5 ways.

Ok, new answer... 1/(5^2) has a pattern where the digits to the right of the decimal place are powers of 2. 2, 4, 8, 16, 32... and so on. Finding the sum of these digits we get 2=2, 4=4, 8=8, 1+6=7, 3+2=5, 6+4=10, and 1+2+8=11. 128 is 2^7 so your answer is 7.

Hope it helps!