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A better explanation would be that we cannot solve the value for x because we do not know the coordinates for the center of the circle.

There is no specific value since the circle can change

10 grams

thanks so much, heureka!!!! it was correct!

(e/10^11.8)       is this part written correctly?       is it supposed to be   e^{-10^11.8}       or  what?

I DID write it in detail.....You should be able to do this

= 4/3  pi  2³ =   33.51  mm³

^{divide by 8   to get volume of smaller droplets = 4.189 mm^3}

4.189   = 4/3 pi r³

^{1 = r^3}          now  find r ....haha

(2 1/4 )/4 = 9/4  / 4  =   9/16  each

Good point.

what two numbers multiply to 17  

If fractions can be used, then 8.5 x 2 is one example. Another is 4.25 x 4.  If you mean integers, see above. 

1 and 17, -1 and -17 are the only answers because 17 is prime.

A semicircle is 180^o so unless I'm missing something, x = 180^o – 148^o = 32^o 

_.

825 x 25

You'll have to be a bit more specific and provide more info...

volume of sphere =  4/3 pi r³

find the original volume   = 4/3  pi  2³  =........

then divide that volume by 8     to find the volume of the smaller spheres   v_1/8

then use the formula again      v_1/8 =  4/3 pi r³      and solve for the  new r of the smaller droplets

360° - 128° - 138° = 94°

94° : 2 = 47°

7 out of  (7+12 +6)    = (c)Rap music    7 / 25

7/25  x 1250 = ........

[(1.585 x 10-5 x 9.81) + (1.585 x 10-3 x 2.61) + (3.162 x 10-3 x 1.8)] / 14.222 = 0.0731261425959781

just pasted it into web2 calculator......

This is a straightforward Pythagorean Theorem problem....

  the car distances are each of the legs of a right triangle  .... one is 15 km...and the hypotenuse is 17 km... find the other leg

c^2 = a^2 + b^2          c = 17   a =15     find  b

Question with bracket

[(1.585 x 10-5 x 9.81) + (1.585 x 10-3 x 2.61) + (3.162 x 10-3 x 1.8)] / 14.222

The opening bracket  '  [ '   is missing the closing bracket  '  ]  '

Right on the money!:

12345 , 12354 , 12435 , 12453 , 12534 , 12543 , 13245 , 13254 , 13425 , 13452 , 13524 , 13542 , 14235 , 14253 , 14325 , 14352 , 14523 , 14532 , 15234 , 15243 , 15324 , 15342 , 15423 , 15432 , 21345 , 21354 , 21435 , 21453 , 21534 , 21543 , 23145 , 23154 , 23415 , 23451 , 23514 , 23541 , 24135 , 24153 , 24315 , 24351 , 24513 , 24531 , 25134 , 25143 , 25314 , 25341 , 25413 , 25431 , 31245 , 31254 (50th number).

I would use cosin rule

c^2  = a^2 + b^2 - 2ab cos c

174^2   =   78^2   +   135^2   -   2 (78)(135) cos c                  solve for cos c     then find  angle measure c   via   arc cos

plug in  t= 1       to find s = displacment = -4 cm

  @       t = 2                  s = +4

So in one second from   1  to 2    displacement   chages by   8           average velocity is   8 cm / 1 sec   = 8 cm/sec

do similar for the other time frames

b.   since it asks for an estimate.....try to estimate the slope of the equation at t= 1

                it is negative  

        it is NEARLY a straight line between  t = .5   (value ~ 3)  to  t = 1   (value = -4)

              slope =     ( 3 - - 4) / (.5 - 1) =  -7/.5 = -14

     approx -14 cm/sec

Here is a desmos graph which ma help you ....

https://www.desmos.com/calculator/fkg8uqs8z0

See this link:  https://web2.0calc.com/questions/please-help_39260