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can you edit/comment on the posts with the lengths and variable names? i think they got fussed up in the conversion of \(\LaTeX\).

the number of trailing zeros is determined by how many powers of \(10\) are in the final product. \(25\) has two powers of \(5\), \(150\) has two powers of \(5\) and one power of \(2\), and \(2008\) has three powers of \(2 \). once we count the exponents, we have a total of nine powers of \(2\) and eighteen powers of \(5\), which gives us a total of nine powers of \(10\), giving us \(\boxed{9}\) trailing zeros.

if one of the angles is \(60^\circ\), then we know the rhombus is made up of four 30-60-90 right triangles, with the hypotenuses making up the perimeter. we know that the hypotenuse is \(8\div4=2\), so one leg has a length of \(1\) and the other leg is the length \(\sqrt3\). this means that the lengths of the diagonals are \(2\) and \(2\sqrt3\), so the area of the rhombus is \(2 \times 2\sqrt3 = \boxed{4\sqrt3}\).

You do realize anyone who posts on this forum is 'cheating' considering people ask full question and 9 times out of 10 recieve full answers. I'm sure you've totally never cheated on something in your entire life lighten up mate - not to mention I would be totally fine with someone just giving me steps to solve it since learning on a computer is hard for me and that's what it's come to. 

since it's pairs, the only unit fraction that is large enough to fit this requirement is \(\frac12\), so the only pair is \((\frac12,\frac12)\).

Gee,  thanx for just giving answers, Wizard!

Jeff runs  900-800 = 100 fet per minute faster than Nikaroo

  Jeff will cover 500 ft     in     500ft/ 100ft/min = 5 minutes

900 choices less the choices of  1 and 900 = 898 choices  (it says BETWEEN 1 and 900...I assume not inclusive)

498   are less than 500  

498/898 = 249/449

Wow !  Questions like these just seem like busy-work.

Box surface area= 4(16x11)+ 2(11x11)  in²      we will need to subtract the area of the bottom of the cylinder  BUT we need to add the top surface of the cylinder when we calculate the surface area of the cylinder .....so just compute the surface area of the box and add the lateral area of the cylinder

    cylinder lateral area =  pi x d x h =  pi x 8 x 9 in²

Add the reds to get total in²

h=12 and w=8

Just using a calculator and putting in the values shows x = 27

What your Q describes is

(d-5)/d    is the original

now subtract 3 from numerator and add 2 to the denom   then = 1/2

(d-5-3)/(d+2) = 1/2        now solve for d     then the origianl is     (d-5)/d     

q = quarters        value = 25q

n = nickels  = q-12     value = 5(q-12)

d = dimes= 162- q - (q-12) = 162-2q+12 = 174-2q    value =   10(174-2q)       Summed, these all equal 2200  (22 dollars in cents)

so

25q + 5(q-12)  + 10 (174-2q) = 2200     solve for q    then dimes = 174-2q

Perimeter = H+H+W+W       and H=4+W

SO

40 = 4+W + 4+W +W+W

40=8+4W    Solve for W      then H = 4+W

Just saying your answer is wrong. 

2652/12 is equal to 221

1/221

Jar Jar gets a 1/2 hour head start = 2.5 miles

Darwin is running 7-5 = 2 mph faster

     and will cover the 2.5 miles    in      2.5m / 2m/hr = 1.25 hr = 75 minutes

You are given a standard deck of 52 cards, and you draw two cards.  What is the probability that both cards are Aces?

The first card is picked from 4 aces, and 52 cards. 

The second is picked from 3 aces and 51 cards. 

Multiplying, we get 12/2652. 

Simplifying, Finally we get 1/251

Since similar triangles, 60/80=27/2x so 3/4=27/2x, x=81/8.

You should consider the determinant!

Probably it is the one Melody said and the idea is to use integration by substitution... One way is to set 1/x=u and then see what du is.