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you didn't say what color is which side on each coin???!!

a=2;b=0;c=0;d=0;p=0; cycle:n=a*1000+b*100+c*10+d;if(a!=b and a!=c and a!=d and b!=c and b!=d and c!=d, goto loop, goto next); loop:printn," ",;p=p+1; next:d++;if(d<10, goto cycle, 0);d=0;c++;if(c<10, goto cycle, 0);d=0;c=0;b++;if(b<10, goto cycle,0);b=0;c=0;d=0;a++;if(a<7, goto cycle,0);print"Total = ",p

OUTPUT = 2,520 such numbers. Or: 6 x 9 x 8 x 7 =2,520 permutations

Answer: 3/4 points higher

James croses out to scores that are 83.

86-83=3 now its 3 points below average.

the remaining 8 scores are six points above average=6/8=3/4.

a  =  c^{2c - b}

If  c = 2,  then  a = 4:     a  =  c^{2c - b}     --->     4  =  2^{2·2 - b}     --->    4  =  2^{4 - b}

                                           --->     4  =  2⁴ / 2^b     --->     4·2^b  =  2⁴     --->    4·2^b  =  16

                                                     --->     2^b  =  4     --->     2^b  =  2²     --->     b  =  2

If  c = 3,  a  =  c^{2c - b}     --->     a  =  3^{2·3 - 2}     --->    a  =  3⁴     --->     a  =  81

I don't understand the rest of the question.

why is this post invisible to normal users, melody, are you moderator, did you block this post??????????????? Why?????????????

Solve:  |x + 1| + |x - 1| > 3

Divide into sections:

1)  If  x  >=  1:     (x + 1) + (x - 1)  >  3     --->     2x  >  3     --->     x  >  1.5

2)  If  x  > -1  and  x  <= 1:    (x + 1) + -(x - 1)  >  3     --->     2  >  3     impossible!

3)  If  x <= -1:  -(x + 1) + -(x - 1)  >  3     --->    -2x  >  3     --->     x  <  -1.5

Final answer:  either   x  <  -1.5   or   x  >  1.5

And that is not how you show any credit for a person's effort.

You can at least say thanks for the effort and explain why you believe it to be wrong.

In fact, you could go through it line by line and explain which line/s you believe to be incorrect.

PQ = 26.

Line 1 has the equation of 3x+4y = -14. I'm going to change this into slope intercept form

4y = -14 - 3x

y = -3x/4 + 7/2 This shows that the slope is -3/4. A  function perpendicular to this would have a slope of 4/3. For 2 linear functions to be perpendicular their slopes must be negative reciprocals. 

So line 2 so far has the equation y = 4x/3 + b

The question gives that this function passes through point -5,7, and we can plug this into the equation

7 = 4(-5)/3 + b

7 = -20/3 + b

b = 7 + 20/3

b = 61/3

The question is asking for m + b

m = 4/3 and b = 61/3

m + b = 65/3

If that is what he/she meant, then I get a different result as follows:

124 , 125 , 126 , 134 , 135 , 136 , 142 , 143 , 145 , 146 , 152 , 153 , 154 , 156 , 162 , 163 , 164 , 165 , 214 , 215 , 216 , 234 , 235 , 236 , 241 , 243 , 245 , 246 , 251 , 253 , 254 , 256 , 261 , 263 , 264 , 265 , 314 , 315 , 316 , 324 , 325 , 326 , 341 , 342 , 345 , 346 , 351 , 352 , 354 , 356 , 361 , 362 , 364 , 365 , 412 , 413 , 415 , 416 , 421 , 423 , 425 , 426 , 431 , 432 , 435 , 436 , 451 , 452 , 453 , 456 , 461 , 462 , 463 , 465 , 512 , 513 , 514 , 516 , 521 , 523 , 524 , 526 , 531 , 532 , 534 , 536 , 541 , 542 , 543 , 546 , 561 , 562 , 563 , 564 , 612 , 613 , 614 , 615 , 621 , 623 , 624 , 625 , 631 , 632 , 634 , 635 , 641 , 642 , 643 , 645 , 651 , 652 , 653 , 654 , Total =  114

So, the probability is: 114 / 6^3 =19 /36

PQ = 12

Right scalene triangle.
Sides: a = 10 b = 24 c = 26

Area: T = 120
Perimeter: p = 60
Semiperimeter: s = 30

Angle ∠ A = α = 22.62° = 22°37'11″ = 0.395 rad
Angle ∠ B = β = 67.38° = 67°22'49″ = 1.176 rad
Angle ∠ C = γ = 90° = 1.571 rad

Height: ha = 24
Height: hb = 10
Height: hc = 9.231

Median: ma = 24.515
Median: mb = 15.62
Median: mc = 13

Inradius: r = 4
Circumradius: R = 13
Area of circumcircle =13^2 x pi
Area of incircle =4^2 x pi
[13^2 x pi] - [4^2 x pi] =153pi

|a + b + c| = 14/3.

(a) What is your expected value for Scholarship A?

p = 11 degrees.

3. The answer is 13/7.

4. The inequality is 2x - 3y + 1 > 0.

When you say "None of them is equal to six", do you mean the sum of each permutation, or 6 itself must not appear in any permutation?