Question 19
NOTE: I do not know this stuff. I am referencing this site
http://zonalandeducation.com/mstm/physics/mechanics/forces/newton/mightyFEqMA/mightyFEqMA.html
It looks pretty good.
u=30m/s, mass=2000kg, Braking force=10000N, v=0, find t
F=ma therefore a=F/m=-10000/2000=-5m/s2
v=u+at
0=30-5t
5t=30
t=6 seconds
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d=ut+(1/2)at2
d=30*6+(1/2)(-5)*36
d=180+-90
distance=90metres I think that D is the answer.
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