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x is 180-165=15 degrees.

Look, please don't cuss on here.

WTF! 

You posted tyour answer 25 minutes after posting the question.  It had 6 views and one of them is your. If you actually want someone to answer, you need to leave it for a day. 

Your answer without the solution process is bullshit! If you have a solution post it tomorrow; there is more than one way to solve this.

Answer is 9

From the picture we know that the diameter of the sphere is equal to the height and "width" of the cylinder. We know that a sphere's volume is \(\frac{4}{3}\pi r^3\) where \(r\) is the radius. We also know that the cylinder's volume is \(\pi r^2 h\) where \(r\) is the radius and \(h\) is the height. But as we said before (because the sphere is inscribed within the cylinder) that the height and "width" (diameter) is the same so we can rewrite that to \(2\pi r^3\). The ratio of it is \(\frac{\frac{4}{3}\pi r^3}{2\pi r^3}\). \(\pi r^3\) cancels out and we are left with \(\frac{\frac{4}{3}}{2}\) simplify that to \(\Rightarrow\) \(\frac{4}{2\times3} \Rightarrow \frac {4}{6}\) . We can simplify that further to \(\frac{2}{3}\) because both are divisible by 2. So the answer is \(\boxed{\frac{2}{3}}\) or \(\boxed{2:3}\)

r = 1

segment arc angle is 180 degrees

The distance between the midpoints of the first and the last parts is=>     sqrt(3)  

Anyone giving up?

(Lol) 

I'm posting the answer!

Side PR is divided by the median into 2 equal line segments.

Median is divided by the centroid into 2 line segments whose ratio is 1:2

ON = QN / 3 = 4

NR = PR / 2 = 7

OR = sqrt ( 4² + 7² ) = 8.062257748    

You're welcome. :)

Never mind.

Thank you guys so much! Your answers were very helpful! I fogot all about lcm...thx!

6 times 7 = 42 

Remeber LCM

They will golf on the same day in lcm(6, 7)=42 days.

Thank you as well! You also deserve 5 stars! You guys are awesome! :)

Thank you so much! Very helpful I give you 5 stars! :)

6 *  1/x  = 9/4    divide both sides by 6

1/x = 9/24

x = 24/9

We need to know what that number is, so we let x be that number.

\(\dfrac6x = \dfrac94\)

Cross-multiplying,

\(9x = 24\)

Dividing by 9 on both sides:

\(x = \dfrac{24}9 = \dfrac83 = 2\dfrac23\)

Let Q(x) be the quotient and R(x) be the remainder:

\(x^{9999} + x^{8888} + x^{7777} + \cdots + x^{1111} + 1 = Q(x) (x^2 - 1) + R(x)\)

If we let x² = 1 on both sides, then it gives \(x^{9999} + x^{8888} + x^{7777} + \cdots + x^{1111} + 1 = R(x)\) when all x²'s are replaced by 1.

We rewrite the expression more explicitly in terms of x².

\(x^{9999} + x^{8888} + x^{7777} + \cdots + x^{1111} + 1 = (x^2)^{4999}\cdot x+ (x^2)^{4444} + (x^2)^{3888}\cdot x + \cdots + (x^2)^{555}\cdot x + 1\)

Replacing all x² by 1:

\(R(x) = x + 1 + x + 1 + x + 1 + x + 1 + x + 1 = \boxed{5x + 5}\)