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Here's a visual guide that might help:

Sorry about the terrible presentation,

GeoGebra froze on me and I am not about to start all over, so i just took a pic.

Now check what i have done by drawing your own pic. I could have made a mistake,

Get a equation for the angle sum of kite XBDC

Get a equation for the angle sum of triangle ABC

Solve simultaneously to find solutions for  alpha and k.

You have to look at each scenario separately and then add them all the probabilities that you get together.

P(1 thrown and 1 while all drawn) = 1/6 *  5/15

P(2 thrown and 2 while all drawn) = 1/6 *  5/15 * 4/14

etc

Have you answered part A yet.

What have you done yourself?

The red triangle has area (1/2)*8*4 = 16 cm².

The circle has area pi*4² = 16pi cm²

Hence probability that oint lis in red triangle = 16/(16pi) = 1/pi;

As follows:

\(\tan\theta = \frac{4}{-3}\\\tan\phi = \frac{-12}{\sqrt{3^2+4^2}}\)

Answered here: https://web2.0calc.com/questions/probability-question_35#r5

x = 2, y = -3/2 

Long division:

What is the length of AB?

2.5/5.8 = 2.7/x

Here is a picture and text to show you how to do it.

Let us have a triangle ABC and a point D on BC such that BD = DC = DA. If angle ABC = 50 degrees, then how many degrees are in angle ACB?

That sounds right to me :)

Hello, Guest!~

We start off with x-5y=13, and 4x-3y=1.

We can rearrange the first equation: x=5y+13.

We can substitute this first, rearranged equation into the second, giving us:

4(5y+13)-3y=1

1=4(5y+13)-3y

1=20y+52-3y

1=17y+52

0=17y+51

-51=17y

y=-3.

Now that we have y, we can use that to find x:

x+15=13

x=-2

So your ordered pair would be: (-2,-3)

Hope that helps!~

-TheLovely1

ilorty:  How many triangles are there and what is their combined area?

1. The constant term is -32.

2. The constant term is 6.

:D 

Oops, I mistook it. Sorry! The answer was correct. (for problem #2)

Thanks!

Oh okay! Understood :)

Okay.. Here is problem 2.

It seems that the questions matches...maybe you saw the wrong answer? 

But, to save you some time, let me use my language to reword geno's answer. (none of this is my credit, it is all theirs :D, so you should thank them for creating the answer)

Oh, no, somebody upvoted everything-now it's back to normal!~

I found that website but I didn't really understand their answer so I came here :)

Ok, thank you! 

No problem! Let me try the other two problems...

To do this, let's find the area of the triangle and the circle.

Triangle:

bh(1/2)=A

b=8

h=4

32(1/2) = 16

Circle:

pi(r^2)=A

pi(16)=A

Area = 16pi

Probability: 16/16pi = 1/pi 

:)