All Answers

+219

-1

So sorry! I didn't realize these problems were already answered...

However, question 2 is a bit different than the link you are referring to, maybe it was a mistake?

Question 4's answer was incorrect. Other than those, your solution, and the one for question 3 were very helpful, thank you so much for those!

Noori

NooriJul 31, 2020

+1252

Start simplifying on each side of numerator and denominator. For example, the first numerator is factored to (3x-7)(x+3).

Then cancel out terms.

CoolStuffYTJul 31, 2020

+1252

Your question is x*3x+1??

CoolStuffYTJul 31, 2020

+1084

@TheLovely1, I have been noticing the same thing. But, I cant see the post that answered this question . Has it been deleted, or was it privately answered? Thanks! (I'm just really curious about this issue)

ilortyJul 31, 2020

+1252

AoPS problem, eh?

Check here, has some hints, I used them for this problem: https://math.stackexchange.com/questions/3647594/single-file-queue-with-people-as-blockers

CoolStuffYTJul 31, 2020

+1084

For your first question, it has already been answered (by me) on this link https://web2.0calc.com/questions/here-s-a-challenge-for-everyone#r5.

Question 2 has also been answered by geno3141 here: https://web2.0calc.com/questions/another-tangent-circle-question-please-explain

Question 3 has been answered by heureka here: https://web2.0calc.com/questions/tangent-question-with-inscribed-angles-please-explain

Question 4 has been answered by Dragan and geusts here: https://web2.0calc.com/questions/help-please-thx_4#r4

(PS, next time, just ask one question at a time, and also, double check to make sure it has not been answered yet, by using the search bar)

By the way, if you missed class, you should always refer to your book or a friend to catch up. This way, you can learn.

Good luck on your math journey!

ilortyJul 31, 2020

+79

Oh, much better. I thought we had a troller hanging about here....

TheLovely1Jul 31, 2020

- 437125102848 x^13 y^5

GuestJul 31, 2020

-1

k works out to 4/11.

GuestJul 31, 2020

By Angle Bisector Theorem:

2.5 / 2.7 = 5.8 / AB

AB = 6.3

GuestJul 31, 2020

+79

Hewo, Otterstar!~

So we have a triangle, ABC, where Point D is on BC, such that BD=DC=DA. (I had to draw it like seven times to get the scale right (I don't know why I bothered to draw it so perfectly)). Now, we're told that ABC is 50.

So, since DA=DC=BD, I'm going ahead and assuming that DA perfectly chops angle ABC in half, meaning, Angle DAC= 50/2=25. (Also BAD but we don't care about that.)

Great. Now what? We still need one more angle to find ACD.

So we go back to the part where ABC is perfectly chopped down in half. That means that angle ADC is 90 degrees, (also ADB but we don't care about that), and so, we have two angles of a triangle, and we need to find the last one...

DAC+ACD+ADC=180

180=DAC+ACD+ADC

180=ACD+90+25

180=ACD+115

65=ACD

(ACD=ACB( Just different ways of saying it))

Therefore, ACD=65, and by extension, ACB=65.

Reply to my answer if I made a mistake, or have any questions!~

-TheLovely1

TheLovely1Jul 31, 2020

+79

Thank you so much, Melody!~