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At first glance, it would appear that x = 2 but that would not be an arithmetic sequence. 

With the values multiplied out, we get 1, x², 9  and so x² has to be 5.  therefore x = sqrt(5) 

_.

we know that 1^2=1 and 3^2=9 so x=sqrt((1+9)/2)=sqrt(10/2)=sqrt5 so out=r final answer is \(\boxed{x=\sqrt5}\)

Well i got even worse like i lost 200 points in 2 days! I think there is this crowd of bullies downvoting people for no reason 

Since this is your homemork, I will walk you through it instead of doing it for you. So: step one

1) Find the area of the rhombus .

2) From the area, find the height using the cylinder (because it is also a paralelogram)

3) The sin of BAD is the height over 6

Good luck!

(please ask me questions if you do not understand my wording)

Look at https://web2.0calc.com/questions/probability-question_35#r5

this is also wrong

Width = ( 86-14 ) / 4

Nevermind 

l  = w+7

perimeter =    2 (w+7)  + 2w = 86

                              w = 18

kx^2 + 3kx -4 = 0     for equal roots, the disciminant of the Quadratic Formula must = 0

b^2 - 4ac

9k^2 - 4(k)(-4) = 0

9k^2 +16k = 0

k = -16 /9     or    0 (throw out)  

I am sorry but this is incorrect I have not yet found another answer but I tryed it and it didn't work. Thank you for trying.

Have you solved this problem? 

I worked out so that Q = (-4,2) and k = 26.

Thank you I got it now!

Multiply out the cubes:

   (n - 1)³  =  n³ - 3n² + 3n - 1

   (n - 2)³  =  n³ - 6n² + 12n - 8

   (n - 3)³  =  n³ - 9n² + 27n - 27

Substitute them into the original problem:

   n³  =  (n - 1)³ + (n - 2)³ + (n - 3)³

   n³  =  [ n³ - 3n² + 3n - 1 ] + [ n³ - 6n² + 12n - 8 ] + [ n³ - 9n² + 27n - 27 ]

Simplify:  0  =  2n³ - 18n² + 42n - 36   --->   0  =  n³ - 9n² + 21n - 18

This can be factored; however, if you cannot find the factor -- and, if the solution is an integer, you

can try each of the factors of -18 -- 1, -1, 2, -2, 3, -3, 6, -6, 9, -9, 18, -18

One ot these is the correct answer ...

Thank you so much!

In relation to the angle, the "37" side is the opposite side and the "41" side is the hypotenuse.

sin(angle)  =  opposite / hypotenuse   --->   sin(angle)  =  37 / 41

                                                            --->          angle  =  sin^-1(37/41)

There are two points of intersection; you found only one.

Find the other point and then find the point halfways between these two points. 

This new point will be the point that the question wants.

(18 nCr 5)*(-3^13)*(2^5)*(x^13)*(y^5) = - 437,125,102,848x^13y^5

oops, I did not see that! Silly me...