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John's day off is every 5th day.
Ling's day off is every 8th and 9th day.
LCM(5, 8) =40 and 365/40 =~ 9 times per year
LCM(5, 9) =45 and 365/45 =~ 8 times per year.
9 + 8 =~17 times per year. 

Angle BAC ≈ 39 degrees

Ashton had two boxes of pencils with fourteen pencils in each box.

He gave six pencils to his brother. How many pencils did Ashton have left?  

(2 x 14) – 6  =  28 – 6  =  22 pencils left   

Since John works 4/5 days and Ling works 7/9 days, the days off they have in common is 365*1/4*2/7, which rounds to 26.

Using the cosine law, I worked out that |u + 2w| = sqrt(47).

707  711  717  722  727  733  737  744  747  755  757  766  767  770  771  772  773  774  775  776  778  779  787  788  797  799  800  808  811  818  822  828  833  838  844  848  855  858  866  868  877  878  880  881  882  883  884  885  886  887   889  898  899  900  909  911  919  922  929  933  939  944  949  955  959  966  969  977  979  988  989  990  991  992  993  994  995  996  997  998 >>  Total =  80 such numbers

Thanks :D

Look under your first post.

6 t - 2/3 + t/5 = 4 + (2 - t)/3 
Solve for t:
(31 t)/5 - 2/3 = (2 - t)/3 + 4

Put each term in (31 t)/5 - 2/3 over the common denominator 15: (31 t)/5 - 2/3 = (93 t)/15 - 10/15:
(93 t)/15 - 10/15 = (2 - t)/3 + 4

(93 t)/15 - 10/15 = (93 t - 10)/15:
1/15 (93 t - 10) = (2 - t)/3 + 4

Put each term in (2 - t)/3 + 4 over the common denominator 3: (2 - t)/3 + 4 = 12/3 + (2 - t)/3:
(93 t - 10)/15 = 12/3 + (2 - t)/3

12/3 + (2 - t)/3 = ((2 - t) + 12)/3:
(93 t - 10)/15 = (-t + 2 + 12)/3

Grouping like terms, -t + 2 + 12 = (12 + 2) - t:
(93 t - 10)/15 = ((12 + 2) - t)/3
279t - 30 =210 - 15t
279t + 15t =210 + 30
294t = 240
t =240 / 294

t =40 / 49

its almost an hour

Find the slope of the line below.

Hello macabresubwoofer!

\(m=\frac{y_2-y_1}{x_2-x_1}=\frac{5-8}{5-1}=-\frac{3}{4}=-0.75\)(B)

  !

Let x represent the sum of the first 25 positive odd integers. Let y represent the sum of the next 25 positive odd integers. What is the value of y - x?

Hello Guest!

\(X=\sum(1,3,5...45,47,49)=25\cdot\frac{1+49}{2}=625\\ Y=\sum(27,29,31...45,47,49)=25\cdot\frac{51+99}{2}=1875\)

\(Y-X=1875-625=1250\)

  !

Two right-angled triangles 30-40-50 put together to form an isosceles triangle ABC.  

thats incorrect

The probability is 2/7.

t = 64/79.

x = 1 , 3 , 5 , 7 , 9 , 11 , 13 , 15 , 17 , 19 , 21 , 23 , 25 , 27 , 29 , 31 , 33 , 35 , 37 , 39 , 41 , 43 , 45 , 47 , 49 , Total =  625

y = 51 , 53 , 55 , 57 , 59 , 61 , 63 , 65 , 67 , 69 , 71 , 73 , 75 , 77 , 79 , 81 , 83 , 85 , 87 , 89 , 91 , 93 , 95 , 97 , 99 , Total =  1875

y - x =1875 - 625 =1,250

(x+4)² + (x+2)² = 10²

^{x = 4}

As follows:

\(\sqrt{\frac{4e}{3f}}=\sqrt{\frac{4\times3ef}{9f^2}}=\frac{2}{3f}\sqrt{3ef}\\ \text{or just }\frac{2\sqrt{3ef}}{3f}\)

The midpoint of the line segment between (x,y) and (2,4) is (-7,0) . Find (x,y) .

Use the formula for summing up an arithmetic sequence:
15/2 * [2*7 + 14D] = - 210, solve for D
7.5 * [14 + 14D] = - 210
105 + 105D = -210
105D = - 210 - 105
105D = - 315
D = - 315 / 105
D = - 3  the common difference

If the 3f isn't under the radical in the original expression, then it's C. 

You just take the 4 out from under the radical.  It should be +2 though. 

Go to WolframAlpha and enter your questions one at a time. Type "differentiate" before you enter your question and it will give you the answer. Good luck.