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One way to do it is just to add the degrees to 1/60 times the minutes plus 1/3600 times the seconds. For example:

$${\mathtt{91}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{35}}}{{\mathtt{60}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{54}}}{{\mathtt{3\,600}}}} = {\mathtt{91.598\: \!333\: \!333\: \!333\: \!333\: \!3}}$$

To partition a positive integer you write it as a sum of other positive integers, all possible ways.

Since there are nearly 200 million ways of partitioning 100, I don't fancy trying to partition 1331 ( = 11³)!

this is how to do them on the web 2 calc

For the second one, -2x² +7x + 15 =0, you could either use the quadratic formula, or do the following:

Divide through by -2

x² - (7/2)*x + (15/2) = 0

This factors as:

(x + 3/2)*(x - 10/2) = 0  or  (x + 3/2)*(x - 5) = 0

This gives the two values for x as x = -3/2 and x = 5

I'll do the first one for you:

-3 = 1 + x/2  

Subtract 1 from both sides

-4 = x/2

Multiply both sides by 2

-8 = x

(or x = -8)

See if you can do the others.  First get the term that doesn't multiply or divide x on the other side of the equation, then multiply or divide both sides of the equation by the term that divides or multiplies the x. 

$$\frac{1}{3}\times x = 5\\\\
x = 3 \times 5\\\\
x = 15$$

-12x + 7 = 4x - 9

Add 12x to both sides

7 = 16x - 9

Add 9 to both sides

16 = 16x

Divide both sides by 16

x = 1

Let length be L and W be width.  Then we have two equations:

L = W + 8   and

2*L + 2*W = 52

Replace L in the second equation using the first equation:

2*(W + 8) + 2*W = 52

So

4*W + 16 = 52

4*W = 36

W = 9

So L = 9 + 8

L = 17 inches

How do I solve for n in: 0.25 = 0.5^n

$$\begin{array}{rcl}
0.25 & = & 0.5^n\\\\
\dfrac{1}{4} &=& \left(\dfrac{1}{2} \right)^n\\\\
\dfrac{1}{2^2} &=& \dfrac{1}{2^n} \\\\
2^2 &=& 2^n \\
2&=& n
\end{array}$$

$$\boxed{n= 2}$$ 

Help

4, 9, 12

12 --> 2*2*3 --> 2^2 * 3^1.

What can make 12?

What's a partition?

Yes, great work, DS! 

So, is it like this?

Note that you don't need to multiply out to solve for x because you already have two factors.

Ok thank you.

Ok for the last one, the folowing is the answer

2*3*5*7=210!

Yep, well you only need one 1^1 since you want only 1 of each number but it doesn't matter much since it's just 1.

So the answer is 105!

Like this?

1^1 * 5^1 * 1^1 * 3^1 * 1^1 * 7^1?

Note that you will see the LCM of all prime numbers is basically the multiplication of all the prime numbers. So, it'll be 3*5*7!