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Use the law of cosines.

7² = 9² + 13² - 2 * 9 * 13 * cos(A)      solve for angle A

Hi, I'm good. Sorry to hard you got hurt. What is the math problem lol?

There are three cases, all are red, all are white and all are blue. 

The total marbles (NOT PROBABILITY) is 15. Next time, look at the transcript or actually pay attention in class.

Thank you all who helped! (jugoslav, I did not ask for the answer, I wanted to do it on my own ... but, honestly, thx.)

Good but bad at the same time because i got hurt

h + k + a + b = -8/3.

The probability is 1/4.

Heather has $27

David has $21

And kevin has $42 

The sum of the even coefficients is 4^32 - 2^32.

400 - 6.25m = 200    What's this?

------------------------------------------------

(400 / 2) / 6.25 = 32 minutes

One question per post! I will solve No. 9

Solve for x:
x^3 - 4 x^2 + x + 26 = 0

The left hand side factors into a product with two terms:
(x + 2) (x^2 - 6 x + 13) = 0

Split into two equations:
x + 2 = 0 or x^2 - 6 x + 13 = 0

Subtract 2 from both sides:
x = -2 or x^2 - 6 x + 13 = 0

Subtract 13 from both sides:
x = -2 or x^2 - 6 x = -13

Add 9 to both sides:
x = -2 or x^2 - 6 x + 9 = -4

Write the left hand side as a square:
x = -2 or (x - 3)^2 = -4

Take the square root of both sides:
x = -2 or x - 3 = 2 i or x - 3 = -2 i

Add 3 to both sides:
x = -2 or x = 3 + 2 i or x - 3 = -2 i

Add 3 to both sides:

x = -2                  or             x = 3 + 2 i               or              x = 3 - 2 i

0.05N  +  0.10 * [11 - N] =0.75, solve for N

N = 7 nickels

11 - 7 = 4 dimes

[7 x 0.05]  +  [4 x 0.10] =0.75 or 75 cents.

It looks a lot scarier than it really is

Just simplify the LHS

for instance the x term will just be    \(x^{r-2-(2r)}=x^{-r-2}\)

Once you have done that then you can equate the powers.

so for the x term

\(x^{-r-2}=x^1\\ so\\ -r-2=1\\ r=-3\)

you can find s and t the same way.

Then you can get the answer.

Please no one over ride my answer.

a=1; b=1;d=25*a +3; if(d==10*b +8, goto4, goto5);printd, a, b; a++;if(a<100, goto2, 0);a=1;b++;if(b<100, goto2, discard=0; 

OUTPUT: There are 2 amounts possible as follows:

28 cents from 1 quarter + 3 cents. Or, from 2 dimes + 8 cents.

78 cents from 3 quarters + 3 cents. Or, from 7 dimes + 8 cents.

a=1; b=1;c=(3*a+7)*(b-4); if(c==2*b*a, goto4, goto5);printc, a, b; a++;if(a<100, goto2, 0);a=1;b++;if(b<100, goto2, discard=0;

OUTPUT: p = 7   and   t = 8. Before drinking coffee, he worked for t = 8 hours per day and solved p=7 problems per hour=7*8=56 problems per day. 

On the day he drank his coffee , he worked for (8 - 4) = 4 hours and solved (3*7 +7) =28 problems per hour for a total of: 28 * 4 = 112 problems on that day.

You just need to add up all the numbers on the diagram, and you'll get the answer.

Sit-circle the total is 50

Stay-circle the total is 29

Roll-circle the total is 34

56.9  -  7 ( 1.8) = ........... C

a^2 + b^2 = (-2)^2 + 3^2 = 13.

The mathematician can solve 12 problems.

20 * pi = 62.83

from -62  thru 62     are abs value less than that....    count them up....don't forget zero

Three marbles are randomly selected, without replacement, from a bag containing two red, two blue and two green marbles. What is the probability that one marble of each color is selected? Express your answer as a common fraction.  

The first marble can be anything.  

The probability of pulling out one is 1.               the probability of this happening is 1                                         (1)  

There are 5 marbles left and 4 of them   

are suitable.  The probability of pulling

out one of those four is 4/5.                               the probability of this and (1) happening is 1 • 4/5 = 4/5            (2)  

There are 4 marbles left and 2 of them  

are suitable.  The probability of pulling  

out one of those two is 2/4.                                the probability of this and (2) happening is 1 • 4/5 • 2/4 = 8/20   (3)   

Reducing the fraction in (3) to lowest terms, the probability of getting one of each color is 2/5  

_.

The slope of the line is 1/5.