All Answers 356462 Answers

Using coordinates, we can find that WX = 56.

I counted them and got

6 of 1 and 0 of the other      (6,0)  (0,6)

5 of 1 and 1 to the other      (6,2)  (2,6)

4 of 1 and 2 of the other      (6,3)  (3,6)                  also (6,2)  (2,6) again

                                            (6,4)  (4,6)

3 each                                  (5,5)

                                             (6,5)  (5,6)

                                             (3,3)

So I counted    12 possibilities

Angles CAD and CBE can be equal!  We can't let A be on BC, but we can adjust the position of B so that AC and BC are very close to each other.  Then if they are close enough, since AD and BE are parallel, we can make anlges CAD and CBE equal.

The probability is 17/120.

You can take f(z) = z - 7 + 4i.

There are 80 ways to place the six people.

Hi Pangolin14. Thank you! Did you try to attach an image? It says Not Available?

To put a little flesh on Guest#1'sanswer, and assuming the question is 

"When b^2 is written in base c, the result is 121_c. When c^2 is written in base b, the result is 71_b."

we have:

w_1 = [-12/5,8/5] and w_2 = [13/5,-7/5].

Hello Noori,

To solve this problem we need to draw a diagram. We know that the tangents will be perpendicular to the radii drawn from their points of tangency, I just proved that yesterday, so we can draw a diagram, assume A' and C' are the centers of the tangent circles. Also, A, B, and C are colinear. Try to find the smallest distance between these lines, and build on this diagram!

(a,b) = (8,-3).

The smallest possible value of x is 12.

The points are 1,5    and    4, 3

....then sqtrt 13 * sqrt 52 = sqrt 676        area = 26 units ²

(a) See the graph below.

(b) g(x) = 2/3*f(3x - 1).

(c) We stretch the graph horiztonally by a factor of 3, then stretch the graph vertically by a factor of 1/2, then shift down 3 units.

BC = x      and FC = x

find BF

x^2 + x^2 = bf^2

2 x^2 =  bf^2

then    bf^2 + x^2 = 20 ^2

           2x^2 + x^2 = 400

            3x^2 = 400

             x = 11.547

Sorry, that's wrong!

This requires finding the DISTANCE between two points. Using the distance formula, for (1,5) and (3,4), we get $\sqrt {5}$, and we also get for (3, 4) and (0, -3) by the distance formula $\sqrt {58}.$ Then we multiply the length times width, $\sqrt{290}$, which cannot be simplified.

Hello Guest,

To solve this problem, we can first use the distance formula. Find the length of the sides first.

(Hint: If you don't know the distance formula, it is: \(d=\sqrt{(x2-x1)+(y2-y1)}\)

Then, using the side lengths, you can apply the formula of b*h where b is the base, and h is the height to the rectangle and find the area. Please let me know if you need more help!

Noori

I already know that's incorrect, and also, please don't give me the answer, read the problem GUEST!