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Juriemagic,

These questions are not making sense. 

I am wondering if you are interpreting them incorrectly.

If possible, could you please post a picture of the actual question?   Like maybe a screenshot. Or a photo.

Also, it might help to know what country you are in as symbols can mean different things in different countries.  

Thanks EP,

I'd put those numbers in parenthesis because you are finding sets.

domain is the x values    { 0,  1,  2,   -4 }

range is the y values    { 1,  -3,  -4  }

Maybe it does not matter, that is just the way I learned it.

How about this:

\((x+y+z)^2=(x^2+y^2+z^2)+2(xy+xz+zy)\qquad \\\text{I have just expanded and simplified}\\ (x+y+z)^2=(9)+2(8)\\ (x+y+z)^2=25\\ x+y+z=\pm5\\ \text{but it has to be positive so}\\ x+y+z=5\)

Well get back to me when you do.

You will have to private message me with the address, otherwise, I will not see it.

Yes, your numbers are wrong.

See the answer here: Check the numbers in your question carefully. 248 maybe 243.

https://web2.0calc.com/questions/help_80499

NOTE: I know almost nothing about vectors:

BUT

Here is a youtube for getting the equation of the plane that passes through 3 specific points

1 - Press "Home" which will get you to the site's Calculator.

2 - Copy and paste it into the Calculator.

3 - Press the "=" key and that should give you the answer.

These are all the possible rolls:

11 , 12 , 13 , 14 , 15 , 16 , 21 , 22 , 23 , 24 , 25 , 26 , 31 , 32 , 33 , 34 , 35 , 36 , 41 , 42 , 43 , 44 , 45 , 46 , 51 , 52 , 53 , 54 , 55 , 56 , 61 , 62 , 63 , 64 , 65 , 66 , Total =  36

Just count the ones that have neither 1 nor 4 in them. I count 16 such numbers. Check my count.

So, the probability is: 16 / 36 = 4 / 9

corrections:::    the measure of angle E is 34.36º

no real solutions

For what values of a does the equation (a^2 + 2a)x^2 + (3a)x+2 = 0 yield no real solutions x? Express your answer in interval notation.

Hello Guest!

\((a^2 + 2a)x^2 + (3a)x+2 = 0\\ \)

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

\(x = {-3a \pm \sqrt{\color{blue}9a^2-4\cdot (a^2+2a)\cdot 2} \over 2\cdot (a^2+2a)}\)    \(\color{blue}(9a^2-4\cdot (a^2+2a)\cdot 2)\ <\ 0\)   

The equation has no real solutions when \(a\in \mathbb{R}\ |0\ <\ a\ <\ 16 \)

  !

The largest such t is 82.

The sum of all possible values of h(x) is 30.

I'm still trying to solve the equation, I didn't get much time before rip f 

 In concave equilateral pentagon ABCDE, Angle A is equal to Angle B is equal to 105 degrees. What is the degree measure of angle E?

x= -272 and y  = 16
x= 16 and y     = -272
x= 18 and y     = 306
x= 34 and y     = 34
x= 306 and y  = 18

could you please explain how you got that answer

The answer is 2/7.

a + b = 95.

Sorry instead of x-1 being more convinient, I meant that it had to be x-1 because if it was 3x-1 it would be 1/3. So it would be (3x-9)(x-1)

However, using 3x-3 we would get (3x-3)(x-3)

https://web2.0calc.com/questions/help-please_66339

This is a bowl shaped parabola

minimum occurs at the vertex

'x' at the vertex can be found by   - b /2a =  - -12/6 = 2

sub in 2 for x

3(2^2) -12(2) + k = 1              1 is the minimum value requested in the Q

12   - 24   + k = 1

k = 13

Here is a graph:   (you can see the minumum value is 1 when k = 13)

https://www.desmos.com/calculator/ar7evacrbn

we have 3x^2-12x+k and one of the roots has to be (x-1) or (3x-1). (x-1) is more convinent so we'll use that. With this, we can add 3 to -12 because -1 will be multiplied by 3, and then we get -9x remaining. So we get the equation is (x-1)(3x-9) and k is 9

hi, 

could you please explain how you got that answer