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Check row No. 6 and No. 20. Remember, the first row is counted as "0th" row.

Close.

@Guest xd

1 - There is only one way of buying a gyroscope which costs 97 confusions as follows:

[8 confusions x 8] + [3 confusions x 11] =64 + 33 =97 confusions

2 - There is NO WAY of buying a math-book page for 69 confusions. In fact, 69 is the largest number that you CANNOT make with 11 and 8 confusions. These are the numbers that you Cannot make with 11 and 8 confusions:

(1, 2, 3, 4, 5, 6, 7, 9, 10, 12, 13, 14, 15, 17, 18, 20, 21, 23, 25, 26, 28, 29, 31, 34, 36, 37, 39, 42, 45, 47, 50, 53, 58, 61, 69) >Total of all numbers that you CANNOT make = 35

Thank you! This was really helpful.

See algebraic solution #2 here:  https://web2.0calc.com/questions/how-do-i-solve-this_22

The length of a rectangle is 3 centimeters more than 3 times the width. If the perimeter of the rectangle is 46 centimeters, find the dimension of the rectangle.     

Call the length L and call the width W  

Here's the relationship between their sizes:                                        L = 3W + 3 

The perimeter is two times the length plus two times the width  

So ...                                                                                              2(L)          + 2(W)  =  46  

Remember L = 3W + 3 so substitute it in the place of L                 2(3W + 3) + 2(W)  =  46  

Multiply it out                                                                                  6W + 6      + 2W    =  46   

Combine like terms                                                                         8W   +   6              =  46   

Subtract 6 from each side                                                              8W                         =  40  

Divide both sides by 8                                                                                            W  =  5  

Plug this back into L = 3W +3                                                          L  =  3(5) + 3 = 15 + 3   

                                                                                                                               L  =  18  

_.

Hi Melody, 

sorry it took so long to get back to you. I did more practice and tried integrating g.

I got -1/2 ln|2x|+C. Is that correct?

a=0;p=0; b=0;c=0;d=0;n=a*b+2*a+b;m=b*c+4*b+3*c;l=c*d+8*c+6*d;if(n==348 and m==373 and l==544, goto loop, goto next);loop:p=p+1;printp," =",a,b,c,d;next:a++;if(a<50, goto5,0);a=0;b++;if(b<50, goto5, 0);a=0;b=0;c++;if(c<50, goto5,0);a=0;b=0;c=0;d++;if(d<50, goto5, discard=0;printp

p = 34, q = 8, r = 31, s = 8

The correct answer is     d) L = 18cm; W = 5cm

what is the sum of \(i^{2017}\) , \(i ^{2018}\) , and \(i ^{2019}\) where i = square root of -1?

\(Formula: \boxed{\mathbf{i^n+i^{2+n}=0}}\)

\(\begin{array}{|rcll|} \hline && i^{2017}+i^{2018}+i^{2019} \\ &=& i^{2017}+i^{2019}+i^{2018} \quad | \quad \mathbf{i^{2017}+i^{2019} = 0} \\ &=& 0 + i^{2018} \\ &=& i^{2*1009} \\ &=& \left(i^{2}\right)^{1009} \quad | \quad \mathbf{i^2 = -1} \\ &=& \left(-1\right)^{1009} \\ &=& \mathbf{-1} \\ \hline \end{array}\)

(9x^3-9x^2+18x+5)/(3x-1)

It beats me why any teacher would bother teaching synthetic division.

Normal algebraic division is more logical and more versatile.

First the divisor has to have a coefficient of 1 

\(\frac{9x^3-9x^2+18x+5}{3x-1}\\ =\frac{3(3x^3-3x^2+6x+\frac{5}{3}}{3(x-\frac{1}{3})}\\ =\frac{3x^3-3x^2+6x+\frac{5}{3}}{x-\frac{1}{3}}\)

1/3 |      3      -3            +6          5/3

      |________1____  -2/3_____16/9____

             3        -2         16/3           31/9

So the answer is

\(3x^2-2x+\frac{16}{3}+ \frac{31}{9(x-\frac{1}{3})}\\ =3x^2-2x+\frac{16}{3}+ \frac{31}{3(3x-1)}\\\)

Here is a video people can watch which will explain it.

Each side of quadrilateral ABCD is tangent to a circle. If AB = 84, BC = 78 and CD = 73, find DA.

w + x = 84         x = 84 - w

x + y = 78          y = 78 - x          y = 78 - (84 - w)         y = x - 6

y + z = 73          z = 73 - y          z = 73 - (x - 6)           z = 79 - x

AD = (79 - x) + x = 79

Just look for the pattern

\(i^1=i\\ i^2=-1\\ i^3=-1i\\ i^4=+1\\ i^5=i\\ \text{and so the pattern starts over.} \)

Use the pattern to determine your answers.

The answer is 33.

By computer program p = 34, q = 8, r = 16, and s = 27.

AB² = BC * BD               BC = 4.43908

AD = sqrt(AB² + BD²)

angle BDA = arctan(AB / BD)

r = (AD/2) / cos∠BDA

what is the square root of 1500 over 4 pi?     

Do you mean the square root of the quantity 1500 over 4π ?  

                                 1500               1500

                                ———     =     —–——     =     119.3662  

                                   4π               12.5664

                                 sqrt(119.3662)  =  10.9255    

_.

You are an idiot if all you did was post an answer,,,,sheesh! DF

QP * PC = AP * PB

8 * sqrt(r² + 20²) = (r - 20)*(r + 20)

r = 25.70069473            r² = 660.5257097  

I'm not too sure :(

r^2 = 20.

Only statement A must be true.