listfor(n,1, 25, (1 /(5*n - 2)))==(1 / 3, 1 / 8, 1 / 13, 1 / 18, 1 / 23, 1 / 28, 1 / 33, 1 / 38, 1 / 43, 1 / 48, 1 / 53, 1 / 58, 1 / 63, 1 / 68, 1 / 73, 1 / 78, 1 / 83, 1 / 88, 1 / 93, 1 / 98, 1 / 103, 1 / 108, 1 / 113, 1 / 118, 1 / 123). 1/123 would be the 25th term.