show that Ax + By = C and Ax + By = D are parallel lines explain why the restrictions on a,b,c and d are necessary.
(1) Ax+By=C
(2) Ax+By=D
y-intercept(x=0): $$(1)
\begin{array}{rcl}
\quad A*0 + By &=& C \\
By&=&C\\
y_{(x=0)}&=&\frac{C}{B}
\end{array}
\qquad
(2)
\begin{array}{rcl}
\quad A*0 + By &=& D \\
By&=&D\\
y_{(x=0)}&=&\frac{D}{B}
\end{array}$$
x-intercept (y=0): $$(1)
\begin{array}{rcl}
\quad Ax + B*0 &=& C \\
Ax&=&C\\
x_{(y=0)}&=&\frac{C}{A}
\end{array}
\qquad
(2)
\begin{array}{rcl}
\quad Ax + B*0 &=& D \\
Ax&=&D\\
x_{(y=0)}&=&\frac{D}{A}
\end{array}$$
$$slope = -\frac{y_{(x=0)}}{x_{(y=0)}}$$
$$\text{(1) slope} = -\dfrac{
\frac{C}{B}
}{\frac{C}{A}} = -\frac{C}{C}*\frac{A}{B} = -\frac{A}{B}$$
$$\text{(2) slope} = -\dfrac{
\frac{D}{B}
}{\frac{D}{A}} = -\frac{D}{D}*\frac{A}{B} = -\frac{A}{B}$$
slope (1) = slope (2) = $$-\frac{A}{B}$$ , line 1 and line 2 are parallel
