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what is the minimum for this equation, C(x) 0.5x^2+23x-216+2600/x

Minimum c'(x) = 0

$$c'(x) = 2 * 0.5 x +23 -1*(2600)x^{-2}=x +23 -\frac{2600}{x^{2}} = 0\\
c'(x) = 0:\\
x +23 -\frac{2600}{x^{2}} = 0\\
\frac{2600}{x^{2}} = x+23\\
2600 = x^2(x+23)\\
2600 = x^3+23x^2\\
x^3+23x^2-2600=0\\
x= 9.01217 ( \mbox{ and 2 imaginary solutions} )$$

c(9.01217) = 320.38829

Minimum: (9.01217, 320.38829)

Well, DS, if she's the only one, that's not too bad. There are probably twenty others who will say the same thing, but haven't gotten around to it, yet.

Find the Lcm of 32,84,180 ?

Least Common Multiple, you need the prime factorization:

$$\mbox{prime factorization} \\\\
\begin{array}{rccccc}
32 =& 2^{\textcolor[rgb]{1,0,0}{5}}\ *& 3^0 \ *& 5^0 \ *& 7^0\\
84 =& 2^2 \ *& 3^1 \ *& 5^0 \ *& 7^{\textcolor[rgb]{1,0,0}{1}}\\
180 =& 2^2 \ *& 3^{\textcolor[rgb]{1,0,0}{2}} \ *& 5^{\textcolor[rgb]{1,0,0}{1}} \ *& 7^0\\
\hline
\mbox{in each case the biggest exponent}
& 2^{\textcolor[rgb]{1,0,0}{5}}
\ *& 3^{\textcolor[rgb]{1,0,0}{2}}
\ *& 5^{\textcolor[rgb]{1,0,0}{1}}
\ *& 7^{\textcolor[rgb]{1,0,0}{1}} &= 10080 \\
\end{array}$$

LCM of 32, 84, 180 is 10080

10080 = 315 * 32

10080 = 120 * 84

10080 = 56 * 180

I am so glad! I am so happy that I can't even break my smile!

Nataszza ain't a good girl! She told me to F off.

It looks cool too.

If you don't have a belt and if you let it fall...Goodluck

Ok. Next time, tell me. I will tell yah

$${\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{9}} = {\mathtt{12}}$$

First, do the following.

Now, solve the expression.

1/5 + (-4/5)

1/5 - 4/5

(1 - 4) / 5

-3/5.

But great answer, though. Keep it up, or lose the grand war of  Camelot.

What sucks? Is it math?

Oh yeah? Then I guess you want more.

Bring the points, folks!

When you want to be an astronaut, a doctor, etc., you have to be precisely correct, or it can cause death...

well, math is always useful.

We're still friends, ThAnswerGuy... I know yours worth more. Sorry.

2^-0.2 falls in between 0 and 1.

30% of 32

0.3* 32 = 9.6 hours.

I likes it. How do you do that, btw?

f(x) = x^2 - 8x + 15

f(x) = (x - 5)(x - 3)

x - 5 = 0 --> x = 5.

x - 3 = 0 --> x = 3.

x = 3, 5.

that is what I meant, I just forgot what the word was.

what does "sin" mean?

$${\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{2}}$$

$$\mbox{The\;math\;problem\;}1+1\;\mbox{is\;actually\;an\;expression\;not\;an\;equation.}$$

Type this into the on-site calculator located on the home page: 37*sin(25).

Take the arc cos or acos of .9090.

acos(0.9090) = 24.632477317401 = ~ 25^o.

1+1=Windows