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You are given the displacement of   s = 3

    put that in your accel equation to calc accel

okay well how do I solve displacement? The answer for a is a single numerical value, without variables, so I have to be able to solve it somehow.

...uhhh..... there are FOUR vowels......

                       and there are FOUR consonants ......

The acceleration and velocity are dependent on the displacement ....so the displacement still needs to be in the equation for accel.

1 x 128

+ 1 x 64

+ 0 x 32

+ 1 x 16

+ 0 x 8

+ 0 x 4

+ 1 x 2

+ 0 x 1               11010010

Poor number   11   got left out !

sumfor(n, 1, 100, 2^(n-1))==1 2676506002 2822940149 6703205375 mod 7==1

Since there are 3 vowels, we don't have to choose those.

There are 5 consonants, and we have to choose 2. For now, the order doesn't matter, so 5*4/2=10 ways to choose.

So we have to order five distinct items.

There are 5 possibilities for the first letter of the word, 4 for the next, 3 for the middle, 2 for the second-to-last, and only 1 remaining for the last slot.

so 5*4*3*2*1=120. 

10 ways to choose the letters times 120 ways to order those letters =1200 possible words.

The numbers 1-31 with the exceptions of the ones in the set (0,1,2, 4, 8, and 16). 0 isn't in the first set (1-31)

31-5=26 numbers.

3^5^3 is equal to 3^125

6^2^6 is equal to 6^64

6^64 is equal to 3^64 times 2^64.

3^125 is equal to 3^64 times 3^61.

So we find whether 2^64 or 3^61 is greater.

3^61 is greater than 2^61 by a factor of (3/2)^61.

2 has 3 powers remaining.

So the question is whether 8(2^3) or (3/2)^61 is greater.

1.5^7 is 11.

(3/2)^61 is greater so the first one is greater.

[BDF] = [ECF]

AB*BD = AE*EC

3*2 = 4*EC

EC = 6/4 = 3/2

1   and  2 

x = number of 10 dollar increases

then

revenue =( 40000-7000x)(200 + 10x)

             = 8 000 000 + 400,000x  -1,400,000x - 70,000x^2

             -70 x^2 -1000x +8000

max occurs at x = -b/2a

                         =  - -1000/ (-140)= -7.14           -7.14   ten dollar increases is  -71.40185.70

200 -71.40= 128.60    price for max rev      (this assumes a $10 DECREASE will result in 7000 MORE seats sold)

so any further increase in tix price will result in LOWER revenue !!!!      SO they are at max revenue (unless they LOWER prices)

The average is 18.

That's wrong

There are six numbers in the set but we don't count the empty set so 2^6-1=63 numbers

Thank you!

Triangle CBE is isosceles because the square side length is equal to the triangle side length.

TO find the remaining angles, we find the middle angle, and the other two will be half because it is isosceles.

Angle ACB is equal to the squares interior angle plus the interior of the triangle.

90+60=150.

The remaining 2 angles are equal to each other.

So 180-150=30.

30/2=15.

By the Cosine Law, BE  = 1.8794, and

cos angle EBC = (BE^2 + BC^2 - CE^2)/(2*BE*BC) = cos 20, so angle EBC = 20 degrees.

The probability of drawing a red or blue is 3+2/3+2+x

The green probability would be x/3+2+x.

Simplifying we have that 2(3+2)=x.

So 2(5)=10=x.

you need 20% more boxes

20% x 3 hrs =  .2  * 3 = .6 hour       36 minutes more

f(-i) = 1/2.

Sold   1/5   then 4/5 remain

     then sold 2/5 of the remains   sooo   3/5 of the remains are left

75  * 4/5           * 3/5    = ........... copies left

61/13 = 4.692307 692307 6923    see the pattern?

                   453 mod 6 = 3

First one

log (4^2x-1)  = log (3^2x+3)

log 4 (2x-1) = log3 ( 2x+3)

log4 / log3  (2x-1) = 2x+3

    1.2619 (2x-1) = 2x+3             can you take it from here?     the others are similar .....