All Answers 356710 Answers

from same person! 

First, find the days when they will tell the truth. January has 31 days:

Prime: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31

Third: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

The dates on which they will both tell the truth are the 3rd, so there is only 1 date that works.

I'm pleased :)

let x = your entire question

x^2 = 3  + sqrt 3 sqrt......

then x ^2  - x   = 3

x^2 -x-3   = 0                      then as Penguin said...use quadratic formula to find x  ( the positive value)

this is equal to sin (-30) =   - 1/2  

[ABC] = √3 / 4 * AB²

Calculating the area of a hexagon:

AC = 3        MC = 1.5        A'B' = 4         C'N = √12         QN = 1/3(C'N)

CQ = cos30º * MC

CN = CQ - QN

DN = tan30º * CN

[CDE] = DN * CN

Hexagon area = [ABC] - 3[CDE]

Let the entire thing be equal to x. Then,

\(\sqrt{3 + x} = x\)

\(3 + x = x^2\)

Use the quadratic formula to solve for x.

What part do you not 'get' ?

Let minor arc SF be x degrees.

1/2(210 + x) = 130

210 + x = 260

x = 50 degrees

f(-2x) ==> reflect across y-axis, horizontal compression of factor 2

f(-2x) has domain [-4, 2].

(please correct me if i'm wrong)

There is another way.

Area = 1/2 * (base) * (height)

         = 1/2 * 9 * sqrt(5^2 - 3^2)

         = 18

1-9     9 digits

10 - 99    180 digits

100 - 999  2700 digits

    2889 digits so far      3112 more to go

1000 thru xxxx     4 digits each

     3112 / 4 = 778   more numbers to write beginning with 1000 

             last number will be 1777           and   7   will be the 6001 digit...

Add the two equations together ...the 3t and  -3t will cancel out

   then you can solve for 's'    

      use this value of 's' in either of the equations to calculate 't' ....

5x+y=31,        y = 31 - 5x

-3x+4y = - 37

-3 x + 4 ( 31 - 5x) = -  37

-3x + 124 - 20x =  - 37

-23x  =  - 161

x =   161/23 = 7              y = 31 - 5x       =31 - 5 (7) =  -4 

r = robert now = 2 c

5 years ago

(r-5) = 3 (c-5)

Sub in r = 2c

(2c - 5)=(3c-15)

   10 = c                     r = 2c = 20 y/o

Thanks for the explanation 

2^2 * 7  = 28

2^2 * 2  * 3 = 24      GCF = 2²  = 4

Are the dimensions correct on k     W/m-C       or should they be    W / m²- K    ?

The bos has six sides    6 * .4 * .4 = .96 m^2

watts =    .96 m^2  *  .16 W / m²-K   * ( 293.15 - 277.15 K )        =     I do not know if this is correct......I am unfamiliar with the 'k' units in your question...

if the units are correct it MIGHT be

 watts =  .96 m² / (.025m)   * .16 W /m -C  *   ( 20 - 4 C ) = ........... W

No problem! 

Well you rock 👨🏻‍🎤as well! Sorry I'm in a happy mood 🤦🏻‍♀️.

I know I'm not CPhill but the answer's 4 

  5 out of 40 will get  a hat     5/40 = 1/8    ( if all of the sections are of the same size)