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First, you have to find how much each ticket costs. Bob has 20 dollars, and he spends 2/5 of it on the movie ticket. To find this, you can simply do 20*(2/5). You can also see that 1/5 of 20 dollars is 4 because 20/5=4. He used 2/5 which is double of 1/5 which means the ticket is 2*4=8. Using both methods, your answer will be, the movie ticket is 8 dollars. 

Since the problem says that the tickets were the same amount of money, you can make the equation: 8=y*(4/15). The 8 stands for the price of the movie ticket, the y stands for how much money Bill has, and the 4/15 stands for the fraction of Bill's money spent on the movie ticket. As shown above, y*(4/15) will tell you how much 4/15 of y is. 

Solving for y, you get 30. In conclusion, Bill has 30 dollars.

This is my FIRST every response to a question so hopefully this helps :)

(I do all my calculations on paper so you should probably solve the equations yourself to make sure I didn't make any silly mistakes.)

Oh, I'm sorry, I must have messed up on a part.

Well done CubeyThePenguin...!

\((3x - 5) + (x + 1) = 180\)

\(3x-5+x+1=180\)

\(3x+x-5+1=180\)

\(4x-5+1=180\)

\(4x-4=180\)

\(4x-4+4=180+4\)

\(4x=184\)

\(\frac{4x}{4}=\frac{184}{4}\)

\(x=46\)

The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24

The factors of 28 are: 1, 2, 4, 7, 14, 28

Then the greatest common factor is 4.

(This way probably won't work on big numbers, so you should use EP's way.)

PQS is a straight line, so:

(3x - 5) + (x + 1) = 180

4x - 4 = 180

4x = 184

x = 46 degrees

\(-7\left(1+5m\right)-29<300+7m\)

\(-35m-36<300+7m\)

\(-35m-36+36<300+7m+36\)

\(-35m<7m+336\)

\(-35m-7m<7m+336-7m\)

\(-42m<336\)

\(\left(-42m\right)\left(-1\right)>336\left(-1\right)\)

\(42m>-336\)

\(\frac{42m}{42}>\frac{-336}{42}\)

 \(m>-8\)

\(Sin(330)\)

\(=\cos \left(90^{\circ \:}-330^{\circ \:}\right)\)

\(=\cos \left(-240^{\circ \:}\right)\)

\(=\cos \left(240^{\circ \:}\right)\)

\(=-\frac{1}{2}\)

Let's label the children's ages:

Jessica = a

Jeremy = b

Jenna = c

(a + b)/2 = 11 

(a + b + c)/3 = 10

From there, we can simplify:

a + b = 22          . (1)

a + b + c = 30     . (2)

Subtract equation (1) from (2) to get c = 8.

Your right, there is no intersection at x=450.

I only point it there because it is a point mentioned in the question.

v does stand for something, it stands for the income function.

the intersection of the two can be read of my graph.

(But I still do not understand the question properly.)

Could you perhaps post the "figure shown?"

It might help with solving it. :))

=^._.^=

I think that is what I already assumed.

You have 1000 people. 

you know 2 are sick.

You must find them in the quickest possible way.

You can test up to 32 people on mass and if anyone in the sample is positive for illness then you will get a positive result.

If we define the amount he spent after his first item as x. 

x/2-10= 0

x/2 = 10

x = 20.

So he had 20 dollars after he bought the first item. :))

=^._.^=

If a polynomial has a root of the form \(a + \sqrt{b}\) then it must also have another root of the form \(a - \sqrt{b}.\)

So, our quartic is:

\((x - (1 - \sqrt{2}))(x - (1 + \sqrt{2}))(x - (2 + \sqrt{5}))(x - (2 - \sqrt{5}))\)

Imagine the 1,000 people have to send their pool tests over to you because they don't have their own machine but the travel time is too long to be sending new pool tests, so every pool test must be pre-determined before. The goal is to find the least number of pre-determined tests that will always identify which of the two people are sick.

3x 6    x 2    +   18 x12 = ...... in²

Second one

1/2  12 x 16.2      + 1/2 12 x 16.2    +   1/2   9 x 16.2    + 2 * 1/2  4.5  11.12

10. To do that, find the surface area of 3 non-congruent rectangles, and then multiply by 2:

\(2(10\cdot4+10\cdot2+2\cdot4) = 136\)

11. To find the surface area of that, find the area of one of the 4 congruent triangles, multiply it by 4, and then add the area of the square:

\(\frac{6\cdot9}{2}\cdot4+6\cdot6=144\)

This might help: https://courses.lumenlearning.com/math4libarts/chapter/surface-area/#:~:text=The%20area%20of%20the%20net,of%20triangle%20A%20by%202.

On how many days in the month of January would both Mr. Prime and Mr. Third both say that they will lie the next day?

Prime truth days    2  3   5   7   11   13   17   19    23    29    31 

Mr prime will say that he will lie the next day the 3rd (because he is telling the truth) and the 4th

1st  3rd  4th  5th    6th    7th   10th   11th  12th   13th   16th     17th   18th     19th    22nd    23rd   28th   29th  30th  31st

Mr third   

Third truth days   3 6 9 12 15 18 21 24 27 30      will say ' I will be lying tomorrow' on the following days

                    2nd  3rd      5th 6th     8th   9     11 12    14  15     17  18     20 21       23 24     26 27      29 30

I think !  Whew    !

Common days   3  5  6  11 12  17  18 23    29  30       TEN days

I won't do your homework for you, but here's something to get you started.

surface of rectangular pyramid = 

(square) + 4(triangle)

Plug in the values they give you.

Lines WX and TV are parallel, so

77 - 4x = x + 67

10 = 5x

x = 2  ====>  69 degrees

!!!!