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Herons formula is \(\sqrt{s(s-a)(s-b)(s-c)}\), \(s\) is the perimiter divided by 2, and a, b, and c are the side lengths. We sum 13, 14, and 15 to get 42, then we plug in the lengths. \(\sqrt{42(42-13)(42-14)(42-15)}\)\(=\boxed{126\sqrt{58}}\)

if the two points can be the same point, then the answer is $\boxed{\frac{(4+4)\cdot20}{20\cdot20}=\frac25}$

if the two points are different, then the answer is $\boxed{\frac{(4+3)\cdot20}{20\cdot19}=\frac7{19}}$

We ingore the constant, so the sum of the coefficients is 32 - 47 = -15.

Honestly, I rly like graphing problems :P

if it's a reflection, then the line that contains the reflected point and the real point is perpendicular to y=2x+5, so the equation would be y=-1/2x+b, and we can plug in (6,2) for x and y, and we get b=1. now, we can find the intersection, then multiply how much the x coordinate moved and how much the y coordinate moved by 2 and add those to the original point, and voila, we get our answer.

intersection: 0=5/2x+4

5/2x=-4

x=-8/5

y=4/5+5/5=9/5

so the intersection is (-8/5,9/5). 

the x coordinate moved by -38/5, while the y coordinate moved by 1/5, so we need to move the x coordinate by -76/5, and the y coordinate by 2/5, so the coordinate of B=$\boxed{(-\frac{46}{5},\frac{12}{5})}$

the answer is 9 i think.....

false      square is a rectangle with equal sidelengths

             rhombus is s quadrilateral with equal sidelengths   ....so  a square is a rhombus

9 c 2 = 36      9! / (7! 2!) = 36

In her first topping, she has 9 choices. 

In her second topping, she has 8 choices. (not 9 because it can't be the first one she chose)

9*8 = 72 options. 

However, we have to consider that choosing a then b is the same as choosing b then a.

For example, choosing peppers then sausage is the same as sausage then peppers, so we have to divide by 2.

72/2 = 36. 

36 options. :))

=^._.^=

$\boxed{\textbf{True}},$ because rectangles have varying side lengths $a$ and $b$, and when $a=b$ the rectangle is a square. Therefore, rectangles are somtimes squares, but not always.

true

It's an accute triangle so if we extend CH, the base is orthogonal/perpendicular to AB, so we can find ACH easily: 180-(90+43)=$\boxed{47^\circ}$

$\frac{(45+116)(116-45+1)}{2}=\boxed{5796}$

3sqrt3/2=BD*CE/2=(3^2+sqrt3^2)*CE/2=2sqrt3*3/2/2

CE=$\boxed{\frac32}$

6!/3!*2!=720/12=$\boxed{60}$

https://web2.0calc.com/questions/dice-roll_1#r1

Since isosceles, (180-94)/2=43

Given the form of the graph, we notice that this is a parabola, plugging in the two values of x and y, 

$18=ab^2$

$54=ab^3$

sikving the system of two equations, we earn:

$a=2$

$b=3$
Therefore the graph is

$y=2*3^x$

Use pythagorean to find the missing side of the triangle sqrt(20-4)= 4 so the area of the triangle is 4 and the square is also four. Total area is 8 square units.

The diagnols of a rhombus intercect at a right angle and bisect each other so each triangle has side lengths of 6, 8, and the hypotunuse. Using pythagorean each side is 10mm so the perimiter is 40mm.

sin x

amplitude 2

2 sinx

midline y = 10

2 sin x     + 10

period 4

2 sin pi/2 x   + 10

reflected

-2 sin (pi/2 x)   + 10

\(\aleph_0?\)

First round    Start 1024 people

                   512    games     512 people left

                   256     games     256 people left

                   128 games         128 people left                    

                    64 games           64 people left

                     32 games          32 people left  

                     16 games          16 people left                  

                      8 games             8 people left

                      4 games             4 people left

                      2 games             2 people left

                                 only one game left-----   last game for a winner !       A total of  1023 games played

V=73400=68000+1200(n-3)

5400=1200(n-3)=1200(9/2)

so n=3+9/2=$\boxed{15/2 \  years}$ 

(73400- 68000) / 1200    + 3   =   n