All Answers 358150 Answers

So for this we will place 90 in place of x to solve our problem. So lets do it

x=90(x/100 + 1/3)

=90/100 + 1/3 ( and now out here we will first cut the zeroes of 90 and 100 which makes it easier for us to solve )

= 9/10 + 1/3     ( okay so now we will get the same denominators by taking the LCM of 3  and 10 which is 30 and then as 10 times 3 is 30 so we shall multiply 9 as well by 3 and as 3 is ten times 30 so we shall multiply 1 as well by 10 )

= 27/30 + 10/30   

And now I hope u can do th rest yourself ! And still if u don't understand then pls be free to ask! 

CPhill your comments are always interesting! How do u make them, I wish I could make like these but sadly........................my mind is already full with study stuff so fun can't get much place!

no u dont

well easy

I can see how bored u r

whats your question

Zegroes  this can't be solved!there is no equal sign and so we cant take the numbers  variables to the other side to solve it!

5.5+2.25=7.75

7.75÷2=3.875

Kind of. What are the compatible numbers for 88 and 112? There are no fractions and no remainders.

You will find sqrt(1),(4),(9),(16),(27),(36),(49),(64),(81) simple. No other square roots under 100 is as simple as those listed above.

Multiply 36 by 2.54 cm= 91.44 cm

1.6055512754639893 is the anser also heres how 2 do it  6/3 simly put 2 then the squre root of 13 which is 3.6055512754639893 minus 2 is 1.6055512754639893 the hard part is finding the squre root of 13 (number anser) 6/3 = 2 the squre root of 13 3.6055512754639893 - 2 = 1.6055512754639893

We have a sum of cubes...here is the factorization:

(5x + 3) (25x² - 15x + 9)

Find x such that the distance between the points is 15.

(x,11)(-8,-1) 

OK...so we have

√[(-8-x)² + (-1 -11)²] = 15    let's square both sides to get rid of the radical

[(-8-x)² + (-1 -11)²] = 225     simplify

64 + 16x + x² + 144 = 225

x² + 16x + 208 = 225

x² + 16x - 17 = 0           factor

(x - 1) (x +17) = 0

So

x  = 1    or  x = -17

i didnt even come to the forum today!i am so tired of studying the whole day and luckily all chapters are done!

which anonymous one??

Did you write the anonymous one?

im really  glad u both liked those pics!

And Melody , what a nice dream , and that door would look amazing in your mansion!i'd love to visit your mansion!

And CPhill!that picture is beautiful , i wonder , how beautiful it will look when u see the thing in real!wow!

and one more thing , u said this nice cool morning , so when u said this  i could just remember that day when the weather out here was amazing!it was indeed like as if im living in London!what a beautiful weather!it was some days ago!

Anyways i wish u enjoy your morning!its almost 7:17pm out here so my morning is all gone!

actually Melody i was bored so thought to trap someone to talk to!

A really big pie or 9.86960440109

You don't have to find this person Rosala.  Thay have already found you.

You have an anonymous admirer 

so u mean we should find u?lol

See we cant spoon feed everything , u gotta do some yourself so just enter 45 ÷ 2 in the onsite calculator thats on the home page and hit the equal button and you'll get your answer!

2log(x) = log(4x + 3)     note that we can write this as

log ( x² ) = log(4x + 3)     and equating expressions, we have

x² =  4x + 3                     rearranging, we have

x² - 4x - 3 = 0               no factoring is available here, so using the onsite solver, we have

$${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{2}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}} = {\sqrt{{\mathtt{7}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{0.645\: \!751\: \!311\: \!064\: \!590\: \!6}}\\
{\mathtt{x}} = {\mathtt{4.645\: \!751\: \!311\: \!064\: \!590\: \!6}}\\
\end{array} \right\}$$

Note something here...if we write this equation as 2log(x) = log(4x + 3), then we are explicitly assuming that x > 0  and only the positive solution is correct. However, if we write the equation as  log(x²) = log(4x + 3), then both solutions are correct  !!!