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Tan 16 = opp / adj      opp is the altitude = 18000

tan16 = 18 000 / adj        solve for adj    <=======  the horizontal distance

f * p    - 125 i = 10000

5 p    - 125 i = 10000                well obviously  p must have  = 25i in it for the 125 i to disappear

                                 then for the real part     5 (p) = 10 000

                                                                           real part p = 2000

p = 2000 + 25i

3 second head start =   3x 5 = 15 meters

    difference in speed   8- 5 = 3 m/s           15 / 3 = 5 seconds when P catches Q    (this 8 seconds after Q starts)

in 5 seconds P runs   5 * 8 = 40 meters   this is when they are at the same point 

                    60 meters left in the race   will take  P     60 m / 8 m/s = 7.5 seconds to finish

Hey there.

Might need some confirmation on this, but because it is continuous, i think that means that at x=3, the top and bottom are equal to eachother.

so: 3x^2 + 2 = ax - 1

Using this just rearrange and you can find a with x = 3

3*9+2=3*a-1

29=3a-1

30=3a

10=a

Hope this helps, im pretty sure thats how it works :)

The sum of all values of x such that f(x) = 0 is 8.

Try using coordinates.

I put it in and it is wrong, thanks for help anyway, appreciate it.

Awww please don't be sad. 

I was just doing some alcumus and by the time I got 5 questions wrong, I was about to cry. 

Considering I just failed by last 5 algebra problems, idk how much you should trust my answer, but I'll give it a try. 

z = a + bi

b = 0 since we're looking for the real part of z. 

z = a + 0i

a^2 +0i^2 = 1^2

a = +/- 1

Testing for both, a can't be 1, since 1/0 doesn't exist. 

Therefore, a = -1. 

1/(1--1) = 1/2

I hope this helps. :)))

=^._.^=

Thank You!!!!!

yeahhh thats right, I need more sleep lol thats simple 

Smaller number = x         larger number = y

    3 times smaller number = 3x

            and this equals   larger number - 4

3x = y-4

then   larger - smaller = 38 

             y - x = 38                           

                                now you have two equations and two unkowns ( 'x' and 'y' )....do you think you can solve it now?  

6 - 4 2/3

18/3   -  14/3   =   4/3  = 1 1/3 cups left

The function needs to be continuous

sooooo at x = -1      the first two parts need to be equal             ( 4/x has to equal    mx+b   at   x =  -1 )

    and then at x = 1/2    the last two parts need to be equal       

             so you can find m and b  given this restriction...

15 gallons final soln   52%

x  =  amount of 70%           

(15-x) = amount of 40%

amount of ingredients = amount in final soln

.70(x)     +    .40 (15-x)          =     .52(15)      solve for 'x' the amount of 70%         then 15% is   15-x

Thanks! I got it now. I just checked over my work, and realized that I forgot to square the 4! Now, I got 4 and sqrt of 7! Thanks!

t+1 is obviously larger than t-1

assuming t+1 hypotenuse

(t+1)^2 = (t-1)^2  + 4^2

      expand and solve for t

Now   t+1   might be less than 4

then

4^2  = (t+1)^2   + (t-1)^2       expand and solve for more values of 't'

Remenber to check the values ot  t+1   and t-1   to make sure they 'fit' the assumptions

adults = a

kids = k

(1) k+a = 400

(2) 3k + 6a = 1680

(1) *3 = 3k +3a = 1200

(2)-(1) = 3a = 480

a = 160

Adults = 160

Child = 240

BUT....don't forget the circular top        +   pi (4^2)

Plug in your numbers:

(-2-i)(-2+i) (-2+sqrt3)(-2-sqrt3) = 5

In this case you can read the math right in the sentence. Where you see "is" substitute "=", where you see "more" substitute "+" and times is multiplication. So, Y is 2 more than 4 times X becomes Y = 2 + 4X

The second part if straight forward. Their sum is 51. X+Y=37.

Now substitute 2+ 4X for Y in the second equation.

X + 2 + 4X = 37 Combine like terms.

5X + 2 = 37 Subtract 2 from both sides.

5X = 35 Divide both sides by 5.

X=7 Substitute 7 for X into either equation to get that Y =30

y = 4x +2

x +y = 37

x    +    4x+2    = 37

5x = 35     x = 7      then y = 30

I'll guess .....since it has six sides     (6-2)(180=..........^o