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Better:

So I would like to say a lot of the people inside of here spam their questions and don't respond, or after submitting the answer given, say that it is wrong(I have done this before, I don't do it now). This is no respect, just rethink, Melody, Cphill, herueka, Eletric Pavlov, geno, all those people who are on this website answering, they don't get paid, they just want to help you, even if they don't know who you are, can you imagine what kindness they have, contributing so much of their time to help people, and get nothing in return? Just show some respect, just by responding, saying thank you, or telling them how they got it wrong. 💪respect💪

1) 

If she can take the same path again then the shortest path should be to go from

Exeter to Cullompton,

13

Cullompton to Tiverton,

13+8

Tiverton to Crediton,

13+8+11

 Crediton to Exeter,

13+8+11+8

Exeter to Exmouth,

13+8+11+8+10

and back to Exeter.

13+8+11+8+10+10=60 miles

2)  idk

s = son age

r = rob age = 3s

3s + s = 64

     4s = 64

        s = 16  y/o

        r = 3 s = 3(16) = 48 y/o

-2     4    11    12

https://web2.0calc.com/questions/please-help-with-this_13

57179

x+y= 4   * 7

-9x+7y = -84

-

7x+7y = 28

-16x=-56

x=3.5 y=0.5

Should be B

Plug in your values into this method:

https://web2.0calc.com/questions/given-that-the-diagonals-of-a-rhombus-are-always

The length of the arc of the sector is 12 cm.

By using the distance formula, the only possible value of m is 1/2.

Ahh I accidentally missed part of the question, here is the other part, 

Find all values of $m$ such that the foci both lie on the circle $x^2+y^2=16$

New estimates from the International Union for Conservation of Nature show a mid-point estimate of 26,500 (range: 22,000 to 31,000) in 2015. In The State of the Polar Report 2018, zoologist Susan J. Crockford says updates to IUCN data put the new global mid-point estimate at more than 30,000.

okay thank you

(D) works, this is because when multiplying 3/2 by 2 on top and bottom, we can get 6/4, they have a common denominator now.

Try them out!

well ill help on a few of them, but you need to know how to add fractions, and it seems you don't know, here is a lesson, 

to add a fraction, you need the bottom number, or the denominator, for example 1/2, 2 is denominator, to be the same, 

so if it is 1/2+2/4, we can multiply 1/2 by 2 on the denominator and numerator(the number on the top) and get 2/4, 

2/4+2/4=4/4, = 0. Remember that multiplying the numerator and denominator by the same number is multiplying by 1, 

so 1/2*2/2=1/2*1

 Let's try out (A), (b), (C)

for (A)

I am assuming 2 6, is 2/6, so 2/6+8/18=2/6*3/3+8/18, that is 6/18+8/18=14/18 we can divide by 2/2, and that is 7/9

now a smarter way to do this is to subtract 10/12 and 2/6, this is 10/12-4/12=6/12=1/2

now any answer that is "1/2" works

that means

(B)(C) are the only ones that work

thats wrong but thanks

Let the length be "l"

and the width be "w"

I am assuming you mean "l" at the start as it is unspecified on what "rectangular room means" the perimeter? What parameters, so

l=w+5

2l+2w=46

substitue, 

2(w+5)+2w=46

4w=36

w=9

l=14

I am assuming this is some type of assignment, but maybe ask for an idea? Why are you asking us, math intellects, not only have you not specified, but from the information given, you are making us do all the work for you!

We can use simons favorite factoring trick, 

The "xy+5y part can be factored into y(x+5)

We can add 8x so that it is 4x+20 which is 4(x+5), then we can comping and it is (y+4)(x+5)-8x=0

can you take it on?

On both dice, only the faces with the numbers $3,6$ are divisible by $3$. Let $P(a) = \frac{2}{8} = \frac{1}{4}$ be the probability that Juan rolls a $3$ or a $6$, and $P(b) = \frac{2}{6} = \frac 13$ that Amal does. By the Principle of Inclusion-Exclusion,

p = phones

a = accessory =   7+p 

10 p   + 4 (7+p)    = 126

p = 7      then a = 14

Welll     1/2 of the upper square is shaded

the triangle on the bottom is    1/2 * 1/2 * 1/2  of the original area of the lower square

                                                     = 1/8 of the lower square

2 squarea:               [1/2 (square) + 1/8 (square) ] / 2 square   = 5/16 area shaded

The line of the graph needs to be continuous so

at x = 2        ax+3 has to equal   x-5

                      ax+3 = x-5

                       ax = x - 8      at x= 2

                        a(2) = 2-8

                          a = -3

and   at  -2          x-5   has to equal 2x-b

                            x-5 = 2x-b

                            b+5 = x                for x = -2

                             b+5 = -2

                             b = -7

4 - 3 = 2

3 - 1 = 1

3 - 2 = 2

4 - 3 = 1