Let the numbers be a < b < c < d < e
Then the smallest two, a and b, must have sum 16,
a + b = 16
and the largest two, d and e, must have sum 37,
d + e = 37.
Then the middle number c is equal to 66 - (a+b) - (d+e) = 66 - 16 - 37 = 13.
OK. So, the two smallest numbers a and b give the sum of 16, and the third number is 13.
It means that the next sum, 20 (see the condition) is a+c.
It can not be nothing else.
If a + c = 20 and c = 13, then a = 20 - 13 = 7.
It implies b = 16-7 = 9.
So, the first three numbers are a = 7, b = 9 and c = 13.
OK. Now we can make the similar analysis from the other end.
So, the two largest numbers d and e give the sum of 37, and the third number in the descending order is 13.
It means that the next from the largest sum, 34 is e+c.
It can not be nothing else.
If e + c = 34 and c = 13, then e = 34 - 13 = 21.
It implies d = 37-21 = 16.
Thus the numbers are 7, 9, 13, 16 and 21.
Their product is 275184.
hope this helps!