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7/10

3 are striped

total = 10

not = 70%

There are 10 marbles 7 of them are not striped/swirled so that makes it 6/10 marbles are not striped/swirled so the answer would be either 7/10, 70%, 0.7 (there are the same thing)

10 marbles   3 are striped    7 are not       7 out of 10     7/10

Your answer is wrong :(

You would expect 3 because you have an 80% chance of drawing a 3 but you have a 20% chance of drawing a 9 
so you would get 3

1. Three segments have a total length of 26 inches. The first segment is 2 less than three times the second segment. The third segment is 1 more than five times the second segment. What are the lengths of the three segments? 

All three variables must be defined in terms of x.

1st      3x - 2

2nd     x

3rd      5x + 1

3x - 2 + x + 5x + 1 = 26

9x = 27

x = 3

18 / 30 = x / 24              or                 x = (24 * 18) / 30

30x = 24 * 18                                     x = 432 / 30

x = 14.4                                             x = 14.4

9x4 is the same as 9+9+9+9=36 or 4+4+4+4+4+4+4+4+4=36

The numbers, but in word form.

The answer is 13211Q

1.   Q

2.   1Q              One Q (the previous , but in word form)

3.   111Q,          One 1, One Q (11,1Q)

4.   311Q           Three one(s), One Q (31,1Q)

Ans: 13211Q    One three, 2 one, one Q (13, 21, 1Q)

thank you! I knew how to do this part, I got b too, thank you :)

The answer is 10.

Those towers honestly looks like my hand pointing up. 

1. Almost right; you forgot negative values 

(just as a reminder, the sum \(\displaystyle\sum_{n=1}^{\infty}x^n\) where x is a constant only converges when \(-1  by the ratio test.)

So the answer would be \((-\infty, -2)\bigcup(2, \infty)\)

2. The sum \(\displaystyle\sum_{n=1}^{\infty}\left(\dfrac{y}{n}\right)^a\), where y is a constant, only converges when \(a>1\), so the answer is \((1, \infty)\)

A. H (0, 4, 2)  
    D (0, 4, 0)
    G (5, 4, 2)
    F (5, 0, 2)
I don't know about B

Thank you!!!

So in the question, it says it can't start or end with a vowel and the only vowel there is I and out of the 5 letters _ _ _ _ _ we now know that there are 4 possibilities for the 1st and last letter and now there can be 5 each in the middle so our equation is 4*5*5*5*4 which is equal to 2000

9-(1/2)4×48=87

sorry, none of those are correct :(

Note  that we can write  this as

C = 2n^(1/4)  [  20n^(1/8)  + 8n^(1/3)  ] 

C =  2 * 20* n^(1/4 + 1/8)    +  2* 8 * n^(1/4 + 1/3)   

C  =  40 n^(3/8)  + 16 n^(7/12) 

C  =  40 ⁸√ (n³)   +  16 ¹²√ (n⁷)

a = 3

b = 7

Let A  be your current age

(4/5)A  >  (3/4) (A + 1)

(4/5)A - (3/4)A  > 3/4

(1/20)A  > 3/4

A > (3/4)(20)

A >  15

And

(4/5)A  >  (5/6) (A - 2)

(4/5)A  >  (5/6)A  - 5/3

5/3  >  (5/6)A - (4/5)A

5/3  >  (1/30)A

(5/3) ( 30)  > A

50  > A

15  < A  < 50    where A is an integer

Wait... nvm. There's no answer to it.

https://web2.0calc.com/questions/four-fifths-of-my-current-age-is-greater-than-three-quarters-of-my-age-one-year-from-now

Um... CPhill answered this question a couple of years ago, if you want to see the answer.

Area  =  (1/2) height  * ( sum of base lengths)

38  =  (1/2) (4)  ( 10  + x)

38 = 2  ( 10 + x)

38 / 2   =  10 +  x

19  =  10 + x

19 - 10  = x   =  9 =   the other base length

In every  hundred, we will  have  20  integers   that satisfy  this

So    20 (hundreds) * 20 ( occurnces in each hundred)  =  400

And we  have three more occurences  from 2001 - 2012

So

400  + 3   =

403  occurences