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Area of a circle = πr^2. So the area of a circle with a diameter of 8ft, radius of 4ft, is 50.27 or in terms of π (exact value) is 16π. 

Thank you, but it's not the right answer. 

Angle YZX = 65 degrees.

you're welcome. :DDDD

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I got it right! thank you :]

The area of a trapezoid is the average of the 2 bases times the height. In other words,

\(A=\frac{17+39}{2}\cdot16=\boxed{448}\)

To solve for it. 

(y+5)/2 = -2. 

The average of the y coordinate and 5 is equal to -2. 

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so the endpoint is 5 and the middle point is -2 , i dont know how to find the average between the y coordinate and 5 though. would it still be 1 like with the other one?

After solving for x, you also have to solve for y. 

Use the same method as x. :)))

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I solved for x so what would that make the ordered pair...?

helllllpppppppp

Let's think about this one. The mid point is the average of the 2 end poitns. 

X coordinate

The end point is 4 and the middle point is 1. 

The average of the x coordinate and 4 is 1. 

(x+4)/2 = 1

Can you solve for x?

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bumppppppppp

I messed it up sorry!! the real question  is:  

The midpoint of a line segment is located at (1 -2). If one of the endpoints is (4, 5) , what is the other endpoint? Express your answer as an ordered pair.

I think there's a way to edit, but if you can't figure it out, just respond to your question. 

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oh, sorry i must not have gotten the variables in there. is there a way to edit questions on here or do i have to make a whole new one?

I think the question may not have been copied and pasted fully. 

Also, try looking at past questions to try to answer this one. :))

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Midpoint  =

[ (6  + 0) / 2  ,  (12 - 6)/2  ]  =

[ 6/2  , 6/2  ]   =

( 3 , 3)

Sum  =  3 + 3   =  6

Thanks for pointing that out EP   

I was thinking about changing my answer but it is still the same only with a power of 9 instead of 11.

Obviously, the final answer will be different but I don't care so much about my final answers.

It is the method I am showing.

The average of the x coordinates is 1. (1+1)/2

The average of the y coordinates is 7. (4+10)/2

The the coordinates of the midpoitn is (1, 7). 

Hope this helped. :))

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The key to question A is that (a+b)(a-b) = a^2 - b^2

So we can split the question into parts. 

(101+97)(4) + (93+89)(4)...(5+1)(4). 

Which is also equal to 

4(101+97+93+89...+5+1)

4*102*26/2 = 5304. 

Try using the concept of (a+b)(a-b) = a^2 - b^2 for the second problem. :))

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If the perimeter of PQRS is 24, then PS = QR  = (24 - 14)/ 2 = 10/2 = 5

And the area would be the ST x PS = 28

So  ST x 5 = 28    divide both sides by 5

ST = 28/5  = 5.6  

And RT =√[RS^2 - ST^2] =    √[7^2 - 5.6^2 ] = √17.64   = 4.2

So RT + QR  = 4.2 + 5 = 9.2 =  QT

So the perimeter of  rectangle QOST =  2(ST + QT)  = 2(5.6 + 9.2)  = 29.6 units

One side  =  68 / 4   =  17

1/2  the  length  of  the known diagonal  =  16

1/2  the length  of  the unknown diagonal  = sqrt  [ 17^2 - 16^2 ]  = sqrt [ 289 - 256]  =  sqrt 33

Area of rhombus  =  product of diagonals /  2  =

(2 * 16) ( 2 * sqrt 33)  / 2   =  

32*sqrt(33)  units^2