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The third equation has no y-term, so let's eliminate the y-term from the combination of the first two equations.

x + y + 3z  =  10     --->     x -2     --->     -2x - 2y - 6z  =  -20

-4x + 3y + 5z  =  7       --->                      -4x + 3y + 5z  =  7

Add down the columns:                             -6x - z  =  -13   

Since  kx + z  =  3        --->         z  =  3 - kx

Substituting these:        -6x - (2 - 3kx)  =  -15

                                    -6x - 2 + 3kx  =  -15

                                      6x - 2 - 3kx  =  15

                                          6x - 3kx  =  1

                                          3x(2 - k)  =  17

If  2 - k  =  0,  there is no value for x that will result in a product of 10,

so  k = 2  results in no possible solution.

For every other value of k, there will be a value of x that can produce a product of 10.

So the answer is k = 2.

What exactly is the question to this problem?

First what grade are you in?

Second: I only need to know this so I can help

Guest,incorrect answer is 70.

This is a late response but Happy-late-Birthday Melody🎉🎊🎉🎊

I hope you had a great Birthday~Hannah😇😇😇😇

I look forward to helping you, when you need it

You are welcome ! 

Thank you!

If one angle is 90   and the other two are the same....remember they all add to 180 for a triangle

   90   + angle  + angle  = 180

2 angle = 90

angle = 45 degrees

Infinite solutons for this as written..... part of it is missing....

A triangle has a 90° angle, and the other two interior angles are congruent. Explain how to find the measure of one of the two congruent angles.

B = 93 from the diagram

     then    the answer you found for   b   +   c   = 180    ( straight line)

then recall that the sum of angles in a triangle = 180 

     you are given   42    and you found b       42 + b + a = 180     compute  a   

Thank you 

Find angle K first    .... recall that all of the angles in a triangle sum to 180 degrees

Now that you have angle K      angle K and  JKL form a straight line = 180 degrees also

                                                         K + JKL = 180         then you can compute JKL

you ignoring which answer?

Quadratic Equation in Standard Form: ax2 + bx + c = 0. Quadratic Equations can be factored. 

Quadratic Formula: x = −b ± √(b2 − 4ac) 2a. When the Discriminant (b2−4ac) is: positive, there are 2 real solutions.

You asked for a hint, Hope it helps~Hannah

(ignore)

You apparently think I have no tried that. Well, I have and when I try it wont send the email 

Sorry~Hannah

Sorry..... but if you get an account here on web2.0     you can message people  directly without posting on the forum page......   

Answer was shown in above post

        x - 2y -1 < 0     <=========  This is the form requested in the Q

You can calculat the slope betqeen the two lines   as   ( y1-y2) / (x1-x)      but the way this is drawn I think they want you to use

the   'rise over run ' method ( which is really the same thing )

     from the L poin to the R point       the rise  is   -2     the 'run' is 4     so rise/run = -2 / 4  = -1/2   which is the slope , m

slope intercept form of a line     y = mx + b      we found m = -1/2     'b' is the y -axis intercept at 4 (see it?)

                        so your line is    y = -1/2 x + 4     re-arrange to the requested form

                                                1/2x + y  = 4       multiply thru by 2 to get rid of the fraction\    

                                                  x + 2y   = 8       Done!

So that means x < 2y+1 is the answer? Am i correct?

If you want me to leave you alone just say it

~Hannah

OK...here ya go ( image below)    Read carefully so you will understand .....

  Pick two convenient points on the line.....see the ones I picked?

   find the slope between these lines      slope = m = (y1-y2)/(x1-x2) =  (1-0) /( 3-1)   = 1/2

      so your line starts to look like    y = mx + b    <====== 'Slope-Intercept' form of a line

                                                        y = 1/2 x + b      now we need to calculate 'b'     use either of the points in the equation

                               using 3,1           1 = 1/2 (3) + b

                                                             b = - 1/2

                                       Now your line equation is  y = 1/2 x - 1/2

     the shaded area of the graph is everything GREATER than ( above ) the line

                               y > 1/2 x - 1/2     then re-arrange it into the form needed ( as I did in earlier post )  ......        helpful?