Hello :))
Just post your questions here.
That way, other people can also learn from them too.
There are many amazing answerers that will help you, such as CPhill, Melody, EP, etc.
=^._.^=
Remaining
41,54,67-69,71,74,79,82-89,91,93,97
80% done
41,67-100 left
Update
39,41,54-100 left
37=.2th root(2)+(.2)^(-0!)
38=.2th root(2)+h2c0!)!
37 and 38 cleared
label each extorior angle in the daigram and find its degree measure
Modulus = \({ \sqrt{2^2+6^2}}\)
= \({\sqrt{4+36}}\)
= \({ \sqrt{40}}\)
= \({2 \sqrt{10}}\)
Let's assume that Chloe and Sam had \(x\) apples at first.
So then,
\(x+3={60 \over 100}(x+23)\)
\(100x+300=60x+1380\)
\(40x=1080\)
⇒\(x=27\)
∴ Sam had 27 apples at first.
33=(.2)th root(2)+2-0!
34=(.2)th root(2)+2-0
35=(.2)th root(2)+2+0!
36=(20-2)x2
33-36 cleared
Let's assume Ahmed had \(x\) at a first.
∴ Brad had = \({14x \over 5}\)
Now, according to question
\({14x \over 5}-20=x+16\)
\({14x \over 5}-x=16+20\)
\(9x=180\)
\(x=20\)
∴ Ahmed had 20 at first.
Okay
Its given that
\(f(x)= ax^3-6x^2+bx-5\)
When f(x) is divided by x-1 we get remainder
\(r=b-a+1\)
⇒\(b-a+1=-5\)
⇒\(a-b=6\) ...(1)
Now, when f(x) is divided by x+2 we get remainder
\(r' = -8a-2b-29\)
⇒\(-8a-2b-29=53\)
⇒\(-8a-2b=82\)
⇒\(-4a-b=41\) ...(2)
Subtracting eq (1) from (2)
\(-4a-b-a+b=41-6\)
\(-5a=35\)
∴ \(a=-7\)
From eq (1)
\(b=-13\)
Hence the ordered pair (a,b) is (-7,-13).
~Thank You :)
If 2x + 7 is a factor....then -7/2 is a root
Using synthetic division.....
-7/2 [ 6 29 + c + 35 ]
-21 - 28 -7/2 c + 98
_________________________
6 8 c - 28 133 - 7/2 c
133 - 7/2 c = 0
133 = 7/2 c
133 ( 2/7) = c = 38
LOL!!!
I'll see if I can come up with some more tomorrow.....look under this post and check
EPIC
Maybe we should find someone who is good at programming (pun intended)
No program....just off the top of my head.....
I did something like this before.....I don't believe that either me, the questioner (or his teacher) could find all of them....I think we found something like 83 of them
I'll see if I can find the post....
I've done 52 and 48 but you seems like overkilled 48
Do you have a program or sth like that?
(20 - 2 ] * 2 = 36
[ 22 * 2 ] - 0! = 43
[ 2 (20) ] - 2 = 38
[ .2^--2 + 0! ] * 2 = 52
[.2^-2 - 0! ] * 2 = 48
(20/2)^2 = 100
Literally I already know about 4 of them
But still, thx
Here's a few ....maybe I can think of some others
[.2^-2 ] *2 - 0! = 49
[.2^-2] * 2 + 0! = 51
[.2^-2] * 2 / 0! = 50
C (20, 2) / 2 = 95
(2 + 2)! * ( 2! + 0!) = 72
(2 + 2)! + 20 = 44
(.2^-2) + 20 = 45
[ 2^(2! + 0!) ] ^2 = 64
20 + 22 = 42
I don't think thats correct. Since those are all the possible probabilites in the solution space, their sum should equal one, however your answer does not sum up to one.
Similarities:
Circumference and area both include pi in their formulas.
Circumference and area both include the radius.
Differences:
Circumference is measured in units^1 where area is measured in units^2
Circumference=2$\pi$r
area=$\pi$r$^2$
