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Other angles sum up to 240$^\circ$

mean of all 4 numbers:360/4=90

120-90=30

Lowest number: 90-30=$\boxed{60}$

2:4x3 possible ways so 12/72=1/6

6:4x3 possible ways so 12/72=1/6

10:3x2 possible ways so 6/72=1/12

11:4x2 possible ways so 8/72=1/9

15:3x2 possible ways, so 6/72=1/12

20:2x1 possible ways, so 2/72=1/36

Answer:$\boxed{\dfrac16,\dfrac16,\dfrac1{12},\dfrac19,\dfrac1{12},\dfrac1{36}}$

Thanks again!

Yes

but no concatenation like (2-1)0=10

1=2x0+2/2

2=-20+22

3=2x0!/2+2

4=2x0+2+2

5=2-0+2+2

6=2+0+2+2

7=2+0!+2+2

8=2x2x2+0

9=2x2x2+0!

10=sqrt(20/2)^2

11=(2+2)!/2-0!

12=(2+2)!/2-0

13=(2+2)!/2+0!

14=(2+2)!!+2+0!

15=2^(2x2)-0!

16=2^(2+2)+0

17=2^(2+2)+0!

18=(2+2)!-(2+0!)!

19=22-2-0!

20=-2-0+22

21=-2+0!+22

22=2x0+22

23=(2+2)!-2+0!

24=2-0+22

25=(2+2)!+2-0!

26=(2+2)!+2+0

28=22+(2+0!)!

29=(.2)^(-0!)+(2+2)!

30=(2+2)!+(2+0!)!

31=(.2)^(-2)+(2+0!)!

32=2^(2+2+0!)

1.  Divide  the circumference  by  2pi

2.  This gives  the  radius

3.  Plug  the  radius into     pi *  (radius)^2    and Voila  !!!.....that's  the  area

ab = 105.

X=lowest number

extreme right=x+60

middle = x+30

x+60=x+30+x+32 

or

x+60=x+30+x+28

A) 160x6/5=$\boxed{192}$

B) 192x3/4=$\boxed{144}$

C) 160+192+144=$\boxed{496}$

Can  we   combine digits   ???....such as 2, 0  =   20  ????

Thank you!

3/5  = B / 35    cross-multiply

35 * 3  =   5 B

105  = 5 * B

105 / 5  =  B  =   21  slices of  bread

Solve  for the radius

4.71  = 2 (3.14)  *  r

r =   4.71  /   ( 2 * 3.14)  =  .75 ft

Plastic needed    =   (3.14)  (.75)^2   =    1.8  sq ft

P   - .44P   = 39

.56 P =  39

P = 39  / .56  = $69.64   = original price

The original price  has to be greater than the on-sale price

z^49  + z^50  + z^51  + z^52  =

z^49  + z^51  + z^50  + z^52

z^49 ( 1 + z^2)  +  z^50 ( 1 +z^2)

z^49 ( z^2  + 1)  + z^50 ( z^2 + 1)  = 

z^49 (0)  +  z^50 (0)   = 

0

Take  the sine inverse to find  x

arcsin (-7/10)  = x   ≈  -44.43°

If  we need  x to be positive    then   180  +  44.43   =  224.43°

Welcome  !!!!

I think this is the  same problem...see my  answer   : https://web2.0calc.com/questions/help-please_86153

I got the first one! Basically it was super simple but the wording made it confusing. BC and AB had to be reflected on one reflection "line" therefore C is in the same position as A making the answer 0!

thx phil

No prob  !!!!

Drawing  a perpendicular  from the  top left  vertex  to   the  base  forms a 30-60-90  right triangle

The  height   =  sqrt (3)

And  the  base of this triangle  = 1

So...by  symmetry......the  bottom  base of the  trapezoid  =  4

So...the area    =

(1/2) sqrt (3)  (  4 + 2)  =

 ( 3 sqrt  3)    units^2   

thank you

Look at  cases

If  x is an  integer  :    floor (x)  = x     and  floor (-x)  = -x

So    x +  -x  =  0

If  x is not an integer  :  floor (x)  =  x     and  floor (-x)  =  -x  - 1

So  x  +  - x  -1  =   -1

So

We have two possible  values    0   and   -1

ohh yayyy

I'm quite happy. 

I've strugling with this topic for a month in alcumus

complex numbers are very hard :((

=^._.^=