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Thank you for formatting correctly,

x is the cost of one meal if I am not mistaken. So, 2x will be the cost of 2 meals. 7 dollars for snacks, and the total is 19. 

so:

2x + 7 = 19

subtract 7 from both side of the equation

2x = 12

divide 2 from both sides

x = 6

Each meal costs 6 dollars

Oops sorry, here you go!

For the 8th grade trip, each student is given $19 for food.

This covers the cost of 2 meals at x dollars each plus $7 worth of snacks. Write the two-step equation to find how much money the school expects each student will spend per meal.

Please format your question properly

OHH so please let me know if I am wrong but if we move A to where point P is, CA'D would be equal to CBE??

Angle CAD can be equal to angle CBE.  If angles CAD and CBE are not equal, then we can choose a point A' on AD so that angle CA'D is equal to CBE.  So we can move point A to A', and then angles CAD and CBE will be equal.

(x,y) = (6,-2).

The largest possible size is just the GCF of the two numbers:

1575 = 3² * 5² * 7

1485 = 3³ * 5 * 11

GCF = 3² * 5

         =  45

Therefore, the maximum team size is 45 people.

https://web2.0calc.com/questions/help-asap_81716

I believe that the acceleration is just -9.81, since that's the gravity?

=^._.^=

You can also use jiskha

n!   "words"

For  example

EAG......we  can form   3!  =  6  different  "words"

EAG

EGA

GAE

GEA

AGE

AEG

ok thanks 

a lot

Consider   if   c  =  1/2

Then    4x^3+3x^2+2x+1  +  (-1/2)  ( 3-4x+5x^2-8x^3  )   = (11/2) x^2   + 5/2  

We  have  the following  possible  function

h =  A sin (Bt - C)  +  D

A  = the amplitude =  50/ 2   = 25

D  = the   shift   upward     =   25  +  6  =   31

C  =  the  phase shift  =  pi/2

B =  the number  of  periods in 2 pi  =    2pi/10 = pi/5

So....the  function  is

h =  25  sin (( pi  / 5) t  - pi / 2)  +  31

b)  at  12  minutes the height  is    25 sin ( (pi/5) (12)  -  pi/2)  +  31  =

25  sin  [ (12/5)  pi  -  (1/2) pi ]  +  31   =

25 sin  [ 1.9  pi  ]  +  31  ≈ 23.27  m

c)  See  the  graph  here :  https://www.desmos.com/calculator/i5cl7732ha

The  ride  will  be  at   46 m  at about  3.5  min

d )  See the  graph  here  :  https://www.desmos.com/calculator/kxrxtlnhsq

The ride  will  be  above  10m  from about  .913 min (  ≈ 54 sec)  to  about  9  min

lets say there are b boys. This means tehr are 3b/4 girls. b+3b/4=7b/4=63

solving for b, we have

b/4=9

b=36

3/4 x 36 = $\boxed{27}$

Great idea Dennis, be rude to a senior member. 

Show that you have no interest in actually learning anything.

That will get you a lot of worthwhile help in life.   

Yay, way to go Dennis! 

See the following image :

We can  use  similar  triangles to solve  this

Let  X     be  the number of units on the  x axis   that is  to the left  of the point   (-3,0)

Let  A =  (0,0)   Let  B  = (7,0)

The  radius of the  smaller circle = 3  = AC    the  radius of the  large  circle =  4 =  BD

BX  =  10 +  X

AX =  3 +  X

We  have  that

BX / BD   = AX / AC

(10+ X)  /  4  =  ( 3 + X)  /  3     cross-multiply

3 (10 + X)  = 4(3 + X)

30  + 3X  =  12 +  4X

30 - 12  =  4X - 3X

18  = X

The  the coordinates of X  are  (  -3 - 18, 0)   = ( -21, 0 )

We  can find   XC    as    sqrt  ( 21^2  - 3^2)  =   12sqrt (3)

The  tangent  of  angle XAC =  -3 / ( 12 sqrt 3)  =    -1 ( 4sqrt (3))  =  -sqrt (3) / 12

The  equation of  one of  the tangent lines  is

y  = (-sqrt (3)  / 12)   ( x  + 21)

And  the  equation of the other  is   just     y=  (sqrt (3) / 12)  (x + 21)

Your way was not easier or more sensible. If you think about it you will work that out.

I just looked at each term in the first bracket and saw what I could pair it with from the second bracket.

Each of the 5 terms only had at most one pair, that is how it always must be.

By convention, the answers MUST be positive.

75% of 18 is 13.5. 75% is equivalent to 75/100, or 3/4. So 3/4 of 13.5 is 10.125. So you add 13.5 and 10.125 to to get 23.625. But that can't be possible, so we round it up to 24 

You're welcome. :))

=^._.^=