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Nice job, MPS  !!!!!

N(100)  =  (N - 10) (110)

100N =  110N  -  1100

1100 =   110 N - 100N

1100 =  10N

1100 / 10  = N =  110

yeah right

A certain number of men can finish a piece of work in 100 days. If there were 10 men less, it would take 10 days more for the work to be finished. How many men were there originally?

Let m = number of men

Let w = work

Let d = days

We know that m * d = w

Since we are given that m men can finish a piece of work in 100 days, we have

m*100=w

Thus, 100m = w. (1)

We are also given that if there were 10 men less (m-10) it will take 10+100=110 days to finish it.

So we have (m-10)(110)=w,

110m-1100=w. (2)

Now, (1) = (2) because they both have w and so they’re equal.

Thus we have 110m-1100=100m

Subtracting both sides by 100m we have 10m - 1100 = 0.

Adding both sides by 1100 we have 10m = 1100

Dividing both sides by 10 we have m = 110.

Therefore there were 110 men originally.

I believe  the  third  choice is correct

The equation is (x - 2)^2/4^2 + (y + 5)^2/3^2 = 1.

;-; is just a face

...... means that something is left unsaid

=^._.^=

(4a + b)  / (a - 2b)  =  5      cross-multiply

4a + b  =   5 (a - 2b)

4a + b  =  5a  -10b

b + 10b  =   5a  - 4a

11b  =  a         and         a/b  = 11   ⇒   b/a   =  1/11

So

(a + 11b)  /  (a - b)    =

       1                                  1                      1                       2                        2

________        =           ______  =       _______ =           ______     =     __________    = 

 ( a -  b)                       (  a -  b)              (a - b)                 (a - b)                1  -  (b/a)

__________               ________         ______               ______

  ( a + 11b)                   (a + a)                  2a                       a

      2                              2                    2*11             22

_________   =      _________  =       ____  =        ___   =    2.2       

  1  - 1/11                   10 /11                 10               10

Nice. :))

=^._.^=

x = (92*10)/20 = 46 days

You're welcome. :))

=^._.^=

I am pretty sure, so hopefully it's right. :))

=^._.^=

Well, I thought about it, couldn't figure it out, but here's a method you can use if you don't know how to do it. 

Let's say a = 1, 

(4 + b)/(1 - 2b) = 5

20 + 5b = 1 - 2b

7b = -19

b = -19/7

So we have a = 1, b = -19/7, plug that into this equation. :))

(a + 11b)/(a - b) 

=^._.^=

Ty! :) 

One of them says 2x^4... Are you sure thats it?

infinite solutions 

Thanks! :D

Well, looking at both of them, we see x^4, so the largest is x^4

=^._.^=

f(x) has x^3

g(x) has 5x^3

x^3 + 5x^3 = 8x^3

=^._.^=

The first one, it's hard to explain, you just need to visualize it. :))

=^._.^=

The  first  choice is correct.....

(pq^3)^3  *  ( 4p^2q)^2                   p^3 * q^9  * 4^2  * p^4  * q^2           16 p^7 q^11

__________________      =         ________________________    =  ____________  = 

       ( 2pq^2)^3                                  2^3  * p^3  * q^6                             8  p^3 q^6

2 p^4 q^5

The maximum difference between the y-coordinates is 8.

There are 2688 possible seatings.

4x^(1/3)  -  2 x / x^(2/3)   =  7  +  x^(1/3)

4x^(1/3)  - 2x^(1/3)  =  7  +  x^(1/3)

2x^(1/3)  - x^(1/3)  =  7

x^(1/3)  =  7         cube both sides

x =  343

12u^3  +  48u^2v            12u^2   (  u  +  4v)              12u^2

______________  =      _________________  =    ______  =      4u^2

     3u  +  12v                     3   ( u  + 4v)                         3