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That's a wonderful explanation. :DD

But for 3^196 doesn't end with a 7, it ends with a 1. 

When you started counting, you started with a 0 so you have to add 1 spot to it.

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Pls answer! And can you tell me how you got your answer? I am so confused on this topic....Thanks!

Nice work. :)

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You're welcome. :))

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nice!

thanks!

I'll help you get started!

Hint:

Find to volume of the top prism, and then find the volume of the bottem prism and then add them together!

(Remember: Volume of a rectangular prism is all of it's dimision's sides multiplied together! $B*H*D$)

TYSM! It's correcct! 

I got 3          2, -3/2, and 19/4

Do you know the right answer?

Done

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f(x) = 4

The first case, -x + 3, which would be x = -1. 

This works since -1 =< 0. 

The second case, 2x - 5, x = 4.5. 

This works since 4.5 > 0. 

f(x) = -1

The first case -x + 3, x = 2. 

However this does not work since 2 is not less than or equal to 0. 

The second case 2x - 5, x = 2. 

This works since 2 > 0. 

f(f(2)) = 4

f(x) = 4.5

The first case -x + 3, x = -1.5.

This works since -1.5 =< 0

The second case 2x - 5, x = 9.5/2. 

Thiw works since 9.5/2 > 0. 

f(f(-1.5)) = 4

f(f(4.75)) = 4

So we have 3 cases.

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its wrong ;-;

Hello, good luck on your study plan. :))

A tip, find a friend to study with, you're less likely to get distracted if you know that someone is doing it with you. 

As for your question, the best way is to plug in -b/(2a) into x. 

For example, if I have the parabola x^2 + 8x + 16, you already know the x coordinate is -4. (-b/(2a))

Knowing the x, we can plug that in to find the y. 

(-4)^2 + 8(-4) + 16 = 0

So our y coordinate is 0. 

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Here's a more braindead but easy solution with mass points. Assign $A=2$ and $C=1$. Then $D=3$, and $B=3$ so $E=6$ then $F=4$. Hence $[AFC]=\frac{800}{3}$, and then $[BEF]=400\cdot 1/3\cdot 1/2=\frac{200}{3}$. So $[EBA]=400-\frac{800}{3}-\frac{200}{3}=\boxed{\frac{200}{3}}$.

I assume (?) you want to eat as many cheez-it's as possible.

In that case, the width of the first is $\frac{22}{2}-9=2$, and the width of the second is $\frac{20}{2}-5=5$.

So it's a $9\times 2$ rectangle and a $5\times 5$ rectangle. Which has greater area? (In other words, which of $9\times 2$ and $5\times 5$ is larger)

The height could be any positive number that you want it to be

thx!

I've never made one, but I did make one with only Penuet butter. It takes around 13 min and 14 seconds.

Medians AX and BY of triangle ABC are perpendicular at point O. AX = 12 and BC = 10.

a. Find AO and BY

b. Find the length of median CZ

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The Median Theorem states that the medians of a triangle intersect at a point called the centroid that is two-thirds of the distance from the vertices to the midpoint of the opposite sides.

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If AX = 12, then AO = 2/3(AX), and OX = 1/3(AX)     AO = 8       OX = 4

If OX = 4, and BX = 5, then BO = 3        (I'll let you find BY) 

CZ you can calculate using CX, OX, and ∠CXO.          (∠CXO ≈ 143.13º)

This is how:

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When you find -b/2a, (I will call that A)

Plug that(A) back to the equation and then you can solve y.

helppppppp meeeeeee

haha lol, but I really need help

"Asignment"