First, simplify the first equation:
\(x=1+\frac{\sqrt{3}}{x}\\x^2-x=\sqrt{3}\)
Then, notice that \(\frac{1}{(x+1)(x-2)}\) simplifies to \(\frac{1}{x^2-x-2}\), so we can replace it like so:
\(\frac{1}{\sqrt{3}-2}\)
To simplify, just multiply the top and bottom by the conjugate
\(\frac{\sqrt{3}+2}{(\sqrt{3}+2)(\sqrt{3}-2)}\\=\frac{\sqrt{3}+2}{3-4}=\frac{2+\sqrt{3}}{-1}\)
\(|2|+|3|+|-1|=\boxed{6}\)
.